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Question 1 of 30
1. Question
Consider a scenario for the Siberian State Aerospace University Entrance Exam where a newly designed probe is intended to transition from a stable circular orbit around Earth at an altitude of 700 km to a higher circular orbit at an altitude of 5000 km. Assuming a standard Hohmann transfer orbit, what is the cumulative velocity increment, expressed in kilometers per second, that the probe’s propulsion system must provide to complete this orbital maneuver, given Earth’s standard gravitational parameter (\(\mu_{Earth}\)) is approximately \(398,600 \, \text{km}^3/\text{s}^2\)?
Correct
The question probes the understanding of orbital mechanics and the fundamental principles governing spacecraft trajectories, specifically concerning the energy required for orbital transfers. A Hohmann transfer orbit is the most energy-efficient two-impulse maneuver for transferring between two circular coplanar orbits. The energy required for such a transfer is directly related to the change in velocity (\(\Delta v\)) needed at the start and end of the transfer ellipse. The initial orbit is a circular orbit at radius \(r_1\). The velocity in this orbit is \(v_1 = \sqrt{\frac{\mu}{r_1}}\), where \(\mu\) is the standard gravitational parameter of the central body. The transfer orbit is an ellipse with periapsis at \(r_1\) and apoapsis at \(r_2\). The semi-major axis of this transfer ellipse is \(a_{transfer} = \frac{r_1 + r_2}{2}\). The velocity at periapsis of the transfer ellipse is \(v_{p,transfer} = \sqrt{\mu \left(\frac{2}{r_1} – \frac{1}{a_{transfer}}\right)}\). The first impulse is applied at periapsis to increase the spacecraft’s velocity from \(v_1\) to \(v_{p,transfer}\). The required \(\Delta v_1\) is \(v_{p,transfer} – v_1\). The final orbit is a circular orbit at radius \(r_2\). The velocity in this circular orbit is \(v_2 = \sqrt{\frac{\mu}{r_2}}\). The velocity at apoapsis of the transfer ellipse is \(v_{a,transfer} = \sqrt{\mu \left(\frac{2}{r_1} – \frac{1}{a_{transfer}}\right)}\). The second impulse is applied at apoapsis to increase the spacecraft’s velocity from \(v_{a,transfer}\) to \(v_2\). The required \(\Delta v_2\) is \(v_2 – v_{a,transfer}\). The total energy expenditure for the transfer is the sum of the magnitudes of these two velocity changes: \(\Delta v_{total} = |\Delta v_1| + |\Delta v_2|\). Consider a scenario where a spacecraft is to be transferred from a circular orbit of radius \(r_1 = 7000 \, \text{km}\) to a circular orbit of radius \(r_2 = 15000 \, \text{km}\) around Earth. The standard gravitational parameter for Earth is \(\mu_{Earth} \approx 398600 \, \text{km}^3/\text{s}^2\). First, calculate the velocities in the initial and final circular orbits: \(v_1 = \sqrt{\frac{\mu_{Earth}}{r_1}} = \sqrt{\frac{398600}{7000}} \approx \sqrt{56.9428} \approx 7.546 \, \text{km/s}\) \(v_2 = \sqrt{\frac{\mu_{Earth}}{r_2}} = \sqrt{\frac{398600}{15000}} \approx \sqrt{26.5733} \approx 5.155 \, \text{km/s}\) Next, calculate the semi-major axis of the Hohmann transfer ellipse: \(a_{transfer} = \frac{r_1 + r_2}{2} = \frac{7000 + 15000}{2} = \frac{22000}{2} = 11000 \, \text{km}\) Now, calculate the velocities at the periapsis and apoapsis of the transfer ellipse: \(v_{p,transfer} = \sqrt{\mu_{Earth} \left(\frac{2}{r_1} – \frac{1}{a_{transfer}}\right)} = \sqrt{398600 \left(\frac{2}{7000} – \frac{1}{11000}\right)} = \sqrt{398600 \left(\frac{1}{3500} – \frac{1}{11000}\right)}\) \(v_{p,transfer} = \sqrt{398600 \left(\frac{11000 – 3500}{3500 \times 11000}\right)} = \sqrt{398600 \left(\frac{7500}{38500000}\right)} = \sqrt{\frac{2989500000}{38500000}} \approx \sqrt{77.65} \approx 8.812 \, \text{km/s}\) \(v_{a,transfer} = \sqrt{\mu_{Earth} \left(\frac{2}{r_2} – \frac{1}{a_{transfer}}\right)} = \sqrt{398600 \left(\frac{2}{15000} – \frac{1}{11000}\right)} = \sqrt{398600 \left(\frac{1}{7500} – \frac{1}{11000}\right)}\) \(v_{a,transfer} = \sqrt{398600 \left(\frac{11000 – 7500}{7500 \times 11000}\right)} = \sqrt{398600 \left(\frac{3500}{82500000}\right)} = \sqrt{\frac{1395100000}{82500000}} \approx \sqrt{16.91} \approx 4.112 \, \text{km/s}\) Calculate the required velocity changes for each impulse: \(\Delta v_1 = v_{p,transfer} – v_1 = 8.812 – 7.546 = 1.266 \, \text{km/s}\) \(\Delta v_2 = v_2 – v_{a,transfer} = 5.155 – 4.112 = 1.043 \, \text{km/s}\) The total velocity change required for the Hohmann transfer is: \(\Delta v_{total} = \Delta v_1 + \Delta v_2 = 1.266 + 1.043 = 2.309 \, \text{km/s}\) The question assesses the understanding of orbital maneuver design, specifically the Hohmann transfer, which is a foundational concept in astrodynamics taught at institutions like Siberian State Aerospace University. This maneuver is crucial for efficient interplanetary and Earth-orbit transfers. The calculation demonstrates the application of Kepler’s laws and the vis-viva equation to determine the necessary velocity changes. A deep understanding of these principles is vital for designing mission trajectories, optimizing fuel consumption, and ensuring mission success. The ability to calculate these \(\Delta v\) values is a core competency for aerospace engineers, enabling them to evaluate the feasibility and cost-effectiveness of various orbital maneuvers. This question, by requiring the calculation of total \(\Delta v\) for a Hohmann transfer, tests not just recall of formulas but the integrated application of orbital mechanics principles in a practical context relevant to space mission design. It highlights the trade-offs between energy efficiency and transfer time, a key consideration in all space missions undertaken by organizations like those affiliated with Siberian State Aerospace University.
Incorrect
The question probes the understanding of orbital mechanics and the fundamental principles governing spacecraft trajectories, specifically concerning the energy required for orbital transfers. A Hohmann transfer orbit is the most energy-efficient two-impulse maneuver for transferring between two circular coplanar orbits. The energy required for such a transfer is directly related to the change in velocity (\(\Delta v\)) needed at the start and end of the transfer ellipse. The initial orbit is a circular orbit at radius \(r_1\). The velocity in this orbit is \(v_1 = \sqrt{\frac{\mu}{r_1}}\), where \(\mu\) is the standard gravitational parameter of the central body. The transfer orbit is an ellipse with periapsis at \(r_1\) and apoapsis at \(r_2\). The semi-major axis of this transfer ellipse is \(a_{transfer} = \frac{r_1 + r_2}{2}\). The velocity at periapsis of the transfer ellipse is \(v_{p,transfer} = \sqrt{\mu \left(\frac{2}{r_1} – \frac{1}{a_{transfer}}\right)}\). The first impulse is applied at periapsis to increase the spacecraft’s velocity from \(v_1\) to \(v_{p,transfer}\). The required \(\Delta v_1\) is \(v_{p,transfer} – v_1\). The final orbit is a circular orbit at radius \(r_2\). The velocity in this circular orbit is \(v_2 = \sqrt{\frac{\mu}{r_2}}\). The velocity at apoapsis of the transfer ellipse is \(v_{a,transfer} = \sqrt{\mu \left(\frac{2}{r_1} – \frac{1}{a_{transfer}}\right)}\). The second impulse is applied at apoapsis to increase the spacecraft’s velocity from \(v_{a,transfer}\) to \(v_2\). The required \(\Delta v_2\) is \(v_2 – v_{a,transfer}\). The total energy expenditure for the transfer is the sum of the magnitudes of these two velocity changes: \(\Delta v_{total} = |\Delta v_1| + |\Delta v_2|\). Consider a scenario where a spacecraft is to be transferred from a circular orbit of radius \(r_1 = 7000 \, \text{km}\) to a circular orbit of radius \(r_2 = 15000 \, \text{km}\) around Earth. The standard gravitational parameter for Earth is \(\mu_{Earth} \approx 398600 \, \text{km}^3/\text{s}^2\). First, calculate the velocities in the initial and final circular orbits: \(v_1 = \sqrt{\frac{\mu_{Earth}}{r_1}} = \sqrt{\frac{398600}{7000}} \approx \sqrt{56.9428} \approx 7.546 \, \text{km/s}\) \(v_2 = \sqrt{\frac{\mu_{Earth}}{r_2}} = \sqrt{\frac{398600}{15000}} \approx \sqrt{26.5733} \approx 5.155 \, \text{km/s}\) Next, calculate the semi-major axis of the Hohmann transfer ellipse: \(a_{transfer} = \frac{r_1 + r_2}{2} = \frac{7000 + 15000}{2} = \frac{22000}{2} = 11000 \, \text{km}\) Now, calculate the velocities at the periapsis and apoapsis of the transfer ellipse: \(v_{p,transfer} = \sqrt{\mu_{Earth} \left(\frac{2}{r_1} – \frac{1}{a_{transfer}}\right)} = \sqrt{398600 \left(\frac{2}{7000} – \frac{1}{11000}\right)} = \sqrt{398600 \left(\frac{1}{3500} – \frac{1}{11000}\right)}\) \(v_{p,transfer} = \sqrt{398600 \left(\frac{11000 – 3500}{3500 \times 11000}\right)} = \sqrt{398600 \left(\frac{7500}{38500000}\right)} = \sqrt{\frac{2989500000}{38500000}} \approx \sqrt{77.65} \approx 8.812 \, \text{km/s}\) \(v_{a,transfer} = \sqrt{\mu_{Earth} \left(\frac{2}{r_2} – \frac{1}{a_{transfer}}\right)} = \sqrt{398600 \left(\frac{2}{15000} – \frac{1}{11000}\right)} = \sqrt{398600 \left(\frac{1}{7500} – \frac{1}{11000}\right)}\) \(v_{a,transfer} = \sqrt{398600 \left(\frac{11000 – 7500}{7500 \times 11000}\right)} = \sqrt{398600 \left(\frac{3500}{82500000}\right)} = \sqrt{\frac{1395100000}{82500000}} \approx \sqrt{16.91} \approx 4.112 \, \text{km/s}\) Calculate the required velocity changes for each impulse: \(\Delta v_1 = v_{p,transfer} – v_1 = 8.812 – 7.546 = 1.266 \, \text{km/s}\) \(\Delta v_2 = v_2 – v_{a,transfer} = 5.155 – 4.112 = 1.043 \, \text{km/s}\) The total velocity change required for the Hohmann transfer is: \(\Delta v_{total} = \Delta v_1 + \Delta v_2 = 1.266 + 1.043 = 2.309 \, \text{km/s}\) The question assesses the understanding of orbital maneuver design, specifically the Hohmann transfer, which is a foundational concept in astrodynamics taught at institutions like Siberian State Aerospace University. This maneuver is crucial for efficient interplanetary and Earth-orbit transfers. The calculation demonstrates the application of Kepler’s laws and the vis-viva equation to determine the necessary velocity changes. A deep understanding of these principles is vital for designing mission trajectories, optimizing fuel consumption, and ensuring mission success. The ability to calculate these \(\Delta v\) values is a core competency for aerospace engineers, enabling them to evaluate the feasibility and cost-effectiveness of various orbital maneuvers. This question, by requiring the calculation of total \(\Delta v\) for a Hohmann transfer, tests not just recall of formulas but the integrated application of orbital mechanics principles in a practical context relevant to space mission design. It highlights the trade-offs between energy efficiency and transfer time, a key consideration in all space missions undertaken by organizations like those affiliated with Siberian State Aerospace University.
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Question 2 of 30
2. Question
Consider a scenario where a satellite is to be moved from a lower Earth orbit to a higher, geosynchronous orbit around Earth. Within the context of orbital mechanics as studied at Siberian State Aerospace University Entrance Exam, what fundamental principle dictates the most propellant-efficient method for achieving this coplanar circular orbit transfer using two distinct propulsive impulses?
Correct
The question probes the understanding of orbital mechanics and the principles governing spacecraft trajectory adjustments, specifically concerning the Hohmann transfer orbit. A Hohmann transfer is an elliptical orbit used to transfer between two circular orbits of different radii in the same plane. The key to this question lies in understanding that the Hohmann transfer is the *most fuel-efficient* method for such transfers, assuming impulsive velocity changes. While other transfer orbits exist (e.g., bi-elliptic transfers, low-thrust trajectories), the Hohmann transfer is the benchmark for minimum energy expenditure in a two-impulse maneuver. The question asks about the *fundamental principle* of achieving a transfer between two coplanar circular orbits with minimal propellant. This directly points to the Hohmann transfer’s characteristic of minimizing the total change in velocity (\(\Delta v\)), which is directly proportional to propellant consumption in rocket propulsion. Therefore, the concept of minimizing the sum of the velocity changes at the departure and arrival points of the transfer ellipse is central. The other options represent valid concepts in orbital mechanics but do not specifically address the *most fuel-efficient* transfer between coplanar circular orbits using two impulsive burns. For instance, gravitational assists utilize celestial bodies to alter a spacecraft’s trajectory and speed, but this is a different mechanism than a direct orbital transfer and is not inherently the most fuel-efficient for a simple two-orbit transfer. Orbital resonance describes the periodic gravitational influence between orbiting bodies, which is relevant for long-term mission planning but not the primary principle for a single transfer maneuver. Finally, atmospheric drag is a force that opposes motion in an atmosphere and is a concern for spacecraft in low Earth orbit, leading to orbital decay, but it is not a principle for *achieving* an orbital transfer between two distinct orbits.
Incorrect
The question probes the understanding of orbital mechanics and the principles governing spacecraft trajectory adjustments, specifically concerning the Hohmann transfer orbit. A Hohmann transfer is an elliptical orbit used to transfer between two circular orbits of different radii in the same plane. The key to this question lies in understanding that the Hohmann transfer is the *most fuel-efficient* method for such transfers, assuming impulsive velocity changes. While other transfer orbits exist (e.g., bi-elliptic transfers, low-thrust trajectories), the Hohmann transfer is the benchmark for minimum energy expenditure in a two-impulse maneuver. The question asks about the *fundamental principle* of achieving a transfer between two coplanar circular orbits with minimal propellant. This directly points to the Hohmann transfer’s characteristic of minimizing the total change in velocity (\(\Delta v\)), which is directly proportional to propellant consumption in rocket propulsion. Therefore, the concept of minimizing the sum of the velocity changes at the departure and arrival points of the transfer ellipse is central. The other options represent valid concepts in orbital mechanics but do not specifically address the *most fuel-efficient* transfer between coplanar circular orbits using two impulsive burns. For instance, gravitational assists utilize celestial bodies to alter a spacecraft’s trajectory and speed, but this is a different mechanism than a direct orbital transfer and is not inherently the most fuel-efficient for a simple two-orbit transfer. Orbital resonance describes the periodic gravitational influence between orbiting bodies, which is relevant for long-term mission planning but not the primary principle for a single transfer maneuver. Finally, atmospheric drag is a force that opposes motion in an atmosphere and is a concern for spacecraft in low Earth orbit, leading to orbital decay, but it is not a principle for *achieving* an orbital transfer between two distinct orbits.
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Question 3 of 30
3. Question
Consider a satellite launched by Siberian State Aerospace University, currently in a stable circular orbit around Earth. To transition this satellite to an elliptical orbit with a significantly higher apoapsis, what fundamental principle of orbital mechanics must be applied through its propulsion system?
Correct
The question probes the understanding of orbital mechanics and the principles governing spacecraft trajectory adjustments, specifically focusing on the concept of orbital energy and its relationship to velocity changes. To achieve a desired change in orbital energy, a spacecraft must alter its velocity. The magnitude of this velocity change, known as the delta-v (\(\Delta v\)), is directly related to the change in kinetic and potential energy. In orbital mechanics, a Hohmann transfer orbit is an elliptical orbit used to transfer a spacecraft between two circular orbits of different radii in the same plane. The most energy-efficient way to increase orbital altitude (and thus orbital energy) is to perform a burn in the direction of motion at the periapsis (closest point) of the transfer ellipse. Conversely, a burn against the direction of motion at the apoapsis (farthest point) would decrease orbital energy. The question asks about increasing the orbital energy of a satellite in a circular orbit around Earth, as would be relevant for a mission from Siberian State Aerospace University. To increase orbital energy, the satellite’s velocity must increase. This is achieved by firing the engines in the direction of the satellite’s current motion. This propulsive maneuver adds kinetic energy to the satellite, which in turn increases its total orbital energy (the sum of kinetic and potential energy). The resulting orbit will be elliptical, with the burn occurring at the periapsis of this new orbit, and the satellite will reach a higher apoapsis. The magnitude of the velocity change required depends on the initial and final orbital parameters. While specific calculations for \(\Delta v\) are not required for this question, the fundamental principle is that a prograde burn (in the direction of motion) increases orbital energy.
Incorrect
The question probes the understanding of orbital mechanics and the principles governing spacecraft trajectory adjustments, specifically focusing on the concept of orbital energy and its relationship to velocity changes. To achieve a desired change in orbital energy, a spacecraft must alter its velocity. The magnitude of this velocity change, known as the delta-v (\(\Delta v\)), is directly related to the change in kinetic and potential energy. In orbital mechanics, a Hohmann transfer orbit is an elliptical orbit used to transfer a spacecraft between two circular orbits of different radii in the same plane. The most energy-efficient way to increase orbital altitude (and thus orbital energy) is to perform a burn in the direction of motion at the periapsis (closest point) of the transfer ellipse. Conversely, a burn against the direction of motion at the apoapsis (farthest point) would decrease orbital energy. The question asks about increasing the orbital energy of a satellite in a circular orbit around Earth, as would be relevant for a mission from Siberian State Aerospace University. To increase orbital energy, the satellite’s velocity must increase. This is achieved by firing the engines in the direction of the satellite’s current motion. This propulsive maneuver adds kinetic energy to the satellite, which in turn increases its total orbital energy (the sum of kinetic and potential energy). The resulting orbit will be elliptical, with the burn occurring at the periapsis of this new orbit, and the satellite will reach a higher apoapsis. The magnitude of the velocity change required depends on the initial and final orbital parameters. While specific calculations for \(\Delta v\) are not required for this question, the fundamental principle is that a prograde burn (in the direction of motion) increases orbital energy.
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Question 4 of 30
4. Question
Consider a probe launched from Earth with the objective of entering a stable, circular orbit around Mars. Upon arrival in the Martian sphere of influence, the probe is traveling at a significant velocity relative to Mars, a velocity that would allow it to escape Mars’ gravitational pull if uncorrected. To successfully achieve its mission objective of orbiting Mars, what fundamental maneuver must the probe execute?
Correct
The question probes the understanding of orbital mechanics and the fundamental principles governing spacecraft trajectories, particularly in the context of interplanetary missions originating from Earth. The correct answer hinges on recognizing that achieving a stable orbit around a celestial body, such as Mars, requires a precise balance between the spacecraft’s velocity and the gravitational pull of that body. This balance is achieved by decelerating the spacecraft from its heliocentric (Sun-centered) trajectory into a planetocentric (Mars-centered) orbit. Without this deceleration, the spacecraft would either continue on its heliocentric path, potentially missing Mars altogether, or enter an unstable, highly elliptical trajectory that might not be considered a stable orbit. The concept of a Hohmann transfer orbit, while relevant for minimizing fuel expenditure between planets, describes the *transition* to the vicinity of Mars, not the final orbital capture itself. Similarly, increasing velocity would typically lead to escape from a gravitational well, not capture into orbit. Therefore, the critical action for orbital insertion is a controlled reduction in velocity relative to Mars.
Incorrect
The question probes the understanding of orbital mechanics and the fundamental principles governing spacecraft trajectories, particularly in the context of interplanetary missions originating from Earth. The correct answer hinges on recognizing that achieving a stable orbit around a celestial body, such as Mars, requires a precise balance between the spacecraft’s velocity and the gravitational pull of that body. This balance is achieved by decelerating the spacecraft from its heliocentric (Sun-centered) trajectory into a planetocentric (Mars-centered) orbit. Without this deceleration, the spacecraft would either continue on its heliocentric path, potentially missing Mars altogether, or enter an unstable, highly elliptical trajectory that might not be considered a stable orbit. The concept of a Hohmann transfer orbit, while relevant for minimizing fuel expenditure between planets, describes the *transition* to the vicinity of Mars, not the final orbital capture itself. Similarly, increasing velocity would typically lead to escape from a gravitational well, not capture into orbit. Therefore, the critical action for orbital insertion is a controlled reduction in velocity relative to Mars.
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Question 5 of 30
5. Question
Consider a satellite in a highly elliptical Earth orbit with an apogee altitude of 800 kilometers. If a minor orbital correction maneuver is performed that lowers the perigee altitude from 400 kilometers to 350 kilometers, while keeping the apogee altitude unchanged, what is the most likely immediate consequence for the satellite’s orbital lifetime, as understood within the principles of orbital mechanics taught at Siberian State Aerospace University?
Correct
The question probes the understanding of orbital mechanics and the implications of atmospheric drag on spacecraft, a core concept in aerospace engineering relevant to Siberian State Aerospace University’s curriculum. While no direct calculation is needed, the reasoning involves understanding that a lower perigee altitude, even if still within the exosphere, significantly increases the rate of atmospheric drag. This increased drag causes a greater loss of orbital energy per orbit. Consequently, the spacecraft’s orbital velocity will decrease more rapidly, leading to a shorter orbital period and a faster decay of its orbit. The spacecraft will therefore reach a point where it can no longer maintain a stable orbit and will re-enter the Earth’s atmosphere sooner. The other options are less accurate because while all orbits experience some degree of drag, the *rate* of decay is the critical factor. A higher apogee alone doesn’t guarantee a longer orbital lifetime if the perigee is sufficiently low to induce substantial drag. Similarly, increasing orbital inclination or eccentricity without considering the perigee altitude’s interaction with the atmosphere does not directly predict a faster orbital decay. The fundamental principle is that proximity to the denser atmospheric layers, even at extreme altitudes, is the primary driver of drag-induced orbital decay.
Incorrect
The question probes the understanding of orbital mechanics and the implications of atmospheric drag on spacecraft, a core concept in aerospace engineering relevant to Siberian State Aerospace University’s curriculum. While no direct calculation is needed, the reasoning involves understanding that a lower perigee altitude, even if still within the exosphere, significantly increases the rate of atmospheric drag. This increased drag causes a greater loss of orbital energy per orbit. Consequently, the spacecraft’s orbital velocity will decrease more rapidly, leading to a shorter orbital period and a faster decay of its orbit. The spacecraft will therefore reach a point where it can no longer maintain a stable orbit and will re-enter the Earth’s atmosphere sooner. The other options are less accurate because while all orbits experience some degree of drag, the *rate* of decay is the critical factor. A higher apogee alone doesn’t guarantee a longer orbital lifetime if the perigee is sufficiently low to induce substantial drag. Similarly, increasing orbital inclination or eccentricity without considering the perigee altitude’s interaction with the atmosphere does not directly predict a faster orbital decay. The fundamental principle is that proximity to the denser atmospheric layers, even at extreme altitudes, is the primary driver of drag-induced orbital decay.
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Question 6 of 30
6. Question
Consider a scenario where a research satellite, designed for atmospheric studies above the mesosphere, is currently in a stable, near-circular orbit around Earth. To achieve its scientific objectives, mission control at the Siberian State Aerospace University’s ground station initiates a propulsive maneuver to transition the satellite into a higher elliptical orbit, significantly increasing its apogee altitude. This maneuver involves a precisely timed engine burn applied tangentially to the satellite’s velocity vector. Which of the following is the most direct and immediate consequence of this specific propulsive action on the satellite’s orbital characteristics?
Correct
The question probes the understanding of orbital mechanics and the factors influencing satellite trajectory adjustments, specifically concerning the conservation of angular momentum. For a satellite in an elliptical orbit, its angular momentum \(L\) is conserved. Angular momentum is defined as \(L = I\omega\), where \(I\) is the moment of inertia and \(\omega\) is the angular velocity. For a point mass \(m\) at a distance \(r\) from the central body, \(I = mr^2\). Thus, \(L = mr^2\omega\). Since \(v_\perp = r\omega\) (where \(v_\perp\) is the velocity component perpendicular to the radius vector), we can also write \(L = mr v_\perp\). In an elliptical orbit, the distance \(r\) from the central body varies. At periapsis (closest point), \(r\) is minimum, and at apoapsis (farthest point), \(r\) is maximum. Due to the conservation of angular momentum (\(mr v_\perp = \text{constant}\)), as \(r\) decreases (moving towards periapsis), \(v_\perp\) must increase, and as \(r\) increases (moving towards apoapsis), \(v_\perp\) must decrease. When a satellite performs a Hohmann transfer orbit to move from a lower circular orbit to a higher elliptical orbit, it fires its engines at the point of departure (perigee of the transfer ellipse). This burn increases its velocity, imparting the necessary tangential velocity to enter the elliptical transfer orbit. The critical aspect here is that this velocity increase is primarily tangential to the original circular orbit. While the burn adds energy and changes the orbit’s semi-major axis, the immediate effect at the burn point is an increase in the tangential velocity component. This increased tangential velocity, at a given radius, directly corresponds to an increase in angular momentum. The question asks about the immediate consequence of a propulsive maneuver that increases the satellite’s orbital energy and moves it to a higher apogee. This maneuver is typically performed tangentially. Increasing the tangential velocity at a given radius directly increases the angular momentum of the satellite. Therefore, the satellite’s angular momentum will increase. The other options are incorrect: while the orbital period will change, it’s a consequence of the energy change, not the immediate effect of the tangential burn on angular momentum. The orbital eccentricity will also change, but the direct and immediate impact of a tangential velocity increase is on angular momentum. The gravitational force is always directed towards the central body and is not directly altered by the satellite’s propulsive maneuver in terms of its instantaneous magnitude or direction relative to the satellite’s position.
Incorrect
The question probes the understanding of orbital mechanics and the factors influencing satellite trajectory adjustments, specifically concerning the conservation of angular momentum. For a satellite in an elliptical orbit, its angular momentum \(L\) is conserved. Angular momentum is defined as \(L = I\omega\), where \(I\) is the moment of inertia and \(\omega\) is the angular velocity. For a point mass \(m\) at a distance \(r\) from the central body, \(I = mr^2\). Thus, \(L = mr^2\omega\). Since \(v_\perp = r\omega\) (where \(v_\perp\) is the velocity component perpendicular to the radius vector), we can also write \(L = mr v_\perp\). In an elliptical orbit, the distance \(r\) from the central body varies. At periapsis (closest point), \(r\) is minimum, and at apoapsis (farthest point), \(r\) is maximum. Due to the conservation of angular momentum (\(mr v_\perp = \text{constant}\)), as \(r\) decreases (moving towards periapsis), \(v_\perp\) must increase, and as \(r\) increases (moving towards apoapsis), \(v_\perp\) must decrease. When a satellite performs a Hohmann transfer orbit to move from a lower circular orbit to a higher elliptical orbit, it fires its engines at the point of departure (perigee of the transfer ellipse). This burn increases its velocity, imparting the necessary tangential velocity to enter the elliptical transfer orbit. The critical aspect here is that this velocity increase is primarily tangential to the original circular orbit. While the burn adds energy and changes the orbit’s semi-major axis, the immediate effect at the burn point is an increase in the tangential velocity component. This increased tangential velocity, at a given radius, directly corresponds to an increase in angular momentum. The question asks about the immediate consequence of a propulsive maneuver that increases the satellite’s orbital energy and moves it to a higher apogee. This maneuver is typically performed tangentially. Increasing the tangential velocity at a given radius directly increases the angular momentum of the satellite. Therefore, the satellite’s angular momentum will increase. The other options are incorrect: while the orbital period will change, it’s a consequence of the energy change, not the immediate effect of the tangential burn on angular momentum. The orbital eccentricity will also change, but the direct and immediate impact of a tangential velocity increase is on angular momentum. The gravitational force is always directed towards the central body and is not directly altered by the satellite’s propulsive maneuver in terms of its instantaneous magnitude or direction relative to the satellite’s position.
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Question 7 of 30
7. Question
Consider a newly deployed observational satellite operating in a highly elliptical orbit around Earth, with its perigee passing through the upper reaches of the thermosphere. The mission control team at the Siberian State Aerospace University is analyzing telemetry data to predict the satellite’s orbital lifespan. Which of the following atmospheric phenomena, when encountered at perigee, would most significantly contribute to a rapid decay of the satellite’s orbit and a potential premature re-entry into the denser atmosphere?
Correct
The question probes the understanding of orbital mechanics and the principles governing satellite trajectories, particularly in the context of atmospheric drag and orbital decay. While no direct calculation is required, the underlying concept involves the relationship between atmospheric density, velocity, and the rate of orbital energy loss. A higher atmospheric density at a given altitude leads to increased drag. Drag force is generally proportional to the square of the velocity and the atmospheric density. This increased drag results in a loss of kinetic and potential energy, causing the satellite’s orbit to shrink and its altitude to decrease. Therefore, a satellite in a lower Earth orbit (LEO), where atmospheric density is generally higher than in higher orbits, will experience more significant drag. This increased drag leads to a more rapid decay of its orbital parameters, such as semi-major axis and eccentricity, and a shorter orbital lifetime. The Siberian State Aerospace University’s curriculum in astronautics and aerospace engineering emphasizes these fundamental principles for designing and operating spacecraft. Understanding these factors is crucial for mission planning, satellite lifespan prediction, and the development of de-orbiting strategies. The correct answer identifies the primary environmental factor that accelerates orbital decay in the context of atmospheric interaction.
Incorrect
The question probes the understanding of orbital mechanics and the principles governing satellite trajectories, particularly in the context of atmospheric drag and orbital decay. While no direct calculation is required, the underlying concept involves the relationship between atmospheric density, velocity, and the rate of orbital energy loss. A higher atmospheric density at a given altitude leads to increased drag. Drag force is generally proportional to the square of the velocity and the atmospheric density. This increased drag results in a loss of kinetic and potential energy, causing the satellite’s orbit to shrink and its altitude to decrease. Therefore, a satellite in a lower Earth orbit (LEO), where atmospheric density is generally higher than in higher orbits, will experience more significant drag. This increased drag leads to a more rapid decay of its orbital parameters, such as semi-major axis and eccentricity, and a shorter orbital lifetime. The Siberian State Aerospace University’s curriculum in astronautics and aerospace engineering emphasizes these fundamental principles for designing and operating spacecraft. Understanding these factors is crucial for mission planning, satellite lifespan prediction, and the development of de-orbiting strategies. The correct answer identifies the primary environmental factor that accelerates orbital decay in the context of atmospheric interaction.
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Question 8 of 30
8. Question
Consider a scenario where a satellite is tasked with transitioning from a stable, low-altitude circular orbit around Earth to a higher-altitude circular geostationary orbit. To achieve this orbital change, mission planners at the Siberian State Aerospace University’s Department of Aerospace Engineering must carefully orchestrate a series of propulsive maneuvers. What fundamental principle governs the direction and effect of the primary velocity adjustments required to initiate this transfer and subsequently circularize the orbit at the higher altitude?
Correct
The question probes the understanding of orbital mechanics and the principles governing spacecraft trajectory adjustments, specifically focusing on the concept of a Hohmann transfer orbit. A Hohmann transfer is an elliptical orbit that connects two coplanar circular orbits of different radii. The key to answering this question lies in understanding that to move from a lower orbit to a higher orbit, a spacecraft must increase its velocity. This increase in velocity is achieved by firing the engines in the direction of motion, which imparts a tangential impulse. This impulse increases the spacecraft’s kinetic energy and alters its trajectory to an ellipse that intersects the higher orbit. The initial velocity in the lower circular orbit is \(v_1\), and the velocity required at the periapsis of the transfer ellipse (which is at the radius of the initial orbit) is \(v_{transfer\_periapsis}\). To achieve this transfer, the spacecraft must accelerate, meaning \(v_{transfer\_periapsis} > v_1\). Similarly, at the apoapsis of the transfer ellipse, which is at the radius of the higher circular orbit, the spacecraft’s velocity is \(v_{transfer\_apoapsis}\). To enter the higher circular orbit, the spacecraft must match its velocity to the circular velocity of that orbit, \(v_2\). Since the transfer ellipse is moving slower at apoapsis than the circular orbit at that radius, an additional acceleration is required, meaning \(v_2 > v_{transfer\_apoapsis}\). Therefore, two propulsive burns are necessary: one to enter the transfer ellipse from the initial circular orbit, and another to circularize the orbit at the destination radius. The first burn increases velocity, and the second burn also increases velocity. The question asks about the *nature* of these velocity changes. Both maneuvers require an increase in velocity to move to a higher energy orbit. The fundamental principle is that to raise an orbit’s apogee (and thus move to a higher orbit), a prograde (forward) burn is required, which increases the spacecraft’s speed. This is a core concept in astrodynamics taught at institutions like Siberian State Aerospace University, emphasizing the energy changes associated with orbital maneuvers. The efficiency of such transfers, minimizing fuel consumption, is a critical aspect of spacecraft design and mission planning.
Incorrect
The question probes the understanding of orbital mechanics and the principles governing spacecraft trajectory adjustments, specifically focusing on the concept of a Hohmann transfer orbit. A Hohmann transfer is an elliptical orbit that connects two coplanar circular orbits of different radii. The key to answering this question lies in understanding that to move from a lower orbit to a higher orbit, a spacecraft must increase its velocity. This increase in velocity is achieved by firing the engines in the direction of motion, which imparts a tangential impulse. This impulse increases the spacecraft’s kinetic energy and alters its trajectory to an ellipse that intersects the higher orbit. The initial velocity in the lower circular orbit is \(v_1\), and the velocity required at the periapsis of the transfer ellipse (which is at the radius of the initial orbit) is \(v_{transfer\_periapsis}\). To achieve this transfer, the spacecraft must accelerate, meaning \(v_{transfer\_periapsis} > v_1\). Similarly, at the apoapsis of the transfer ellipse, which is at the radius of the higher circular orbit, the spacecraft’s velocity is \(v_{transfer\_apoapsis}\). To enter the higher circular orbit, the spacecraft must match its velocity to the circular velocity of that orbit, \(v_2\). Since the transfer ellipse is moving slower at apoapsis than the circular orbit at that radius, an additional acceleration is required, meaning \(v_2 > v_{transfer\_apoapsis}\). Therefore, two propulsive burns are necessary: one to enter the transfer ellipse from the initial circular orbit, and another to circularize the orbit at the destination radius. The first burn increases velocity, and the second burn also increases velocity. The question asks about the *nature* of these velocity changes. Both maneuvers require an increase in velocity to move to a higher energy orbit. The fundamental principle is that to raise an orbit’s apogee (and thus move to a higher orbit), a prograde (forward) burn is required, which increases the spacecraft’s speed. This is a core concept in astrodynamics taught at institutions like Siberian State Aerospace University, emphasizing the energy changes associated with orbital maneuvers. The efficiency of such transfers, minimizing fuel consumption, is a critical aspect of spacecraft design and mission planning.
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Question 9 of 30
9. Question
Consider a scenario where a newly developed satellite, designed for long-term atmospheric monitoring above the Eurasian landmass, needs to be transferred from its initial low Earth orbit (LEO) to a geostationary orbit (GEO). The mission planners at Siberian State Aerospace University are evaluating propulsion strategies to minimize propellant mass while ensuring mission success. Which of the following propulsion and trajectory design philosophies would most effectively address the dual objectives of fuel efficiency and achievable orbital insertion for this specific transfer, given the constraints of modern spacecraft engineering?
Correct
The question probes the understanding of orbital mechanics and the principles governing spacecraft trajectory adjustments, specifically concerning the Hohmann transfer orbit. A Hohmann transfer is an elliptical orbit used to transfer between two circular orbits of different radii in the same plane. The efficiency of this transfer is paramount in minimizing fuel consumption, a critical factor in space missions, especially those originating from or destined for locations with significant gravitational influence, like Earth. The calculation to determine the velocity change required at periapsis ( \( \Delta v_1 \) ) and apoapsis ( \( \Delta v_2 \) ) for a Hohmann transfer between two circular orbits of radii \( r_1 \) and \( r_2 \) (where \( r_2 > r_1 \)) involves the vis-viva equation. The semi-major axis of the transfer ellipse is \( a_{transfer} = \frac{r_1 + r_2}{2} \). The velocity in the initial circular orbit is \( v_1 = \sqrt{\frac{\mu}{r_1}} \), where \( \mu \) is the standard gravitational parameter. The velocity at periapsis of the transfer ellipse is \( v_{p,transfer} = \sqrt{\mu \left(\frac{2}{r_1} – \frac{1}{a_{transfer}}\right)} \). The velocity at apoapsis of the transfer ellipse is \( v_{a,transfer} = \sqrt{\mu \left(\frac{2}{r_2} – \frac{1}{a_{transfer}}\right)} \). The velocity in the final circular orbit is \( v_2 = \sqrt{\frac{\mu}{r_2}} \). The velocity changes required are: \( \Delta v_1 = v_{p,transfer} – v_1 \) \( \Delta v_2 = v_2 – v_{a,transfer} \) The total \( \Delta v \) for the Hohmann transfer is \( \Delta v_{total} = \Delta v_1 + \Delta v_2 \). The question asks about the *most* efficient method for a spacecraft to transition from a low Earth orbit to a higher geostationary orbit. While a Hohmann transfer is generally the most fuel-efficient two-impulse maneuver for such transfers, the concept of continuous low-thrust propulsion, often employed by electric propulsion systems, offers an alternative. These systems, while requiring longer transit times, can achieve the same orbital change with a lower total \( \Delta v \) over the entire mission duration, effectively minimizing propellant mass. This is because they apply small thrusts over extended periods, allowing the spacecraft to spiral outwards, continuously adjusting its orbit. This approach is particularly relevant for long-duration missions and for spacecraft with limited initial mass, aligning with the practical considerations in aerospace engineering taught at Siberian State Aerospace University. The ability to achieve a higher final orbital energy with less instantaneous velocity change, spread over time, is a key advantage. Therefore, understanding the trade-offs between impulsive maneuvers like the Hohmann transfer and continuous low-thrust trajectories is crucial for advanced spacecraft mission design. The question tests this nuanced understanding of orbital maneuver optimization beyond simple, single-impulse calculations.
Incorrect
The question probes the understanding of orbital mechanics and the principles governing spacecraft trajectory adjustments, specifically concerning the Hohmann transfer orbit. A Hohmann transfer is an elliptical orbit used to transfer between two circular orbits of different radii in the same plane. The efficiency of this transfer is paramount in minimizing fuel consumption, a critical factor in space missions, especially those originating from or destined for locations with significant gravitational influence, like Earth. The calculation to determine the velocity change required at periapsis ( \( \Delta v_1 \) ) and apoapsis ( \( \Delta v_2 \) ) for a Hohmann transfer between two circular orbits of radii \( r_1 \) and \( r_2 \) (where \( r_2 > r_1 \)) involves the vis-viva equation. The semi-major axis of the transfer ellipse is \( a_{transfer} = \frac{r_1 + r_2}{2} \). The velocity in the initial circular orbit is \( v_1 = \sqrt{\frac{\mu}{r_1}} \), where \( \mu \) is the standard gravitational parameter. The velocity at periapsis of the transfer ellipse is \( v_{p,transfer} = \sqrt{\mu \left(\frac{2}{r_1} – \frac{1}{a_{transfer}}\right)} \). The velocity at apoapsis of the transfer ellipse is \( v_{a,transfer} = \sqrt{\mu \left(\frac{2}{r_2} – \frac{1}{a_{transfer}}\right)} \). The velocity in the final circular orbit is \( v_2 = \sqrt{\frac{\mu}{r_2}} \). The velocity changes required are: \( \Delta v_1 = v_{p,transfer} – v_1 \) \( \Delta v_2 = v_2 – v_{a,transfer} \) The total \( \Delta v \) for the Hohmann transfer is \( \Delta v_{total} = \Delta v_1 + \Delta v_2 \). The question asks about the *most* efficient method for a spacecraft to transition from a low Earth orbit to a higher geostationary orbit. While a Hohmann transfer is generally the most fuel-efficient two-impulse maneuver for such transfers, the concept of continuous low-thrust propulsion, often employed by electric propulsion systems, offers an alternative. These systems, while requiring longer transit times, can achieve the same orbital change with a lower total \( \Delta v \) over the entire mission duration, effectively minimizing propellant mass. This is because they apply small thrusts over extended periods, allowing the spacecraft to spiral outwards, continuously adjusting its orbit. This approach is particularly relevant for long-duration missions and for spacecraft with limited initial mass, aligning with the practical considerations in aerospace engineering taught at Siberian State Aerospace University. The ability to achieve a higher final orbital energy with less instantaneous velocity change, spread over time, is a key advantage. Therefore, understanding the trade-offs between impulsive maneuvers like the Hohmann transfer and continuous low-thrust trajectories is crucial for advanced spacecraft mission design. The question tests this nuanced understanding of orbital maneuver optimization beyond simple, single-impulse calculations.
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Question 10 of 30
10. Question
Consider a newly deployed Earth observation satellite at Siberian State Aerospace University, initially positioned in a stable circular orbit at an altitude of 400 kilometers above the Earth’s surface. The mission objective is to transition this satellite to a higher circular orbit at an altitude of 800 kilometers to enhance its observational coverage. Which of the following maneuvers represents the most fuel-efficient and standard approach for achieving this orbital altitude increase, adhering to fundamental principles of astrodynamics taught at Siberian State Aerospace University?
Correct
The question probes the understanding of orbital mechanics and the factors influencing spacecraft trajectory adjustments, specifically concerning the Hohmann transfer orbit. A Hohmann transfer is an elliptical orbit that connects two coplanar circular orbits of different radii. The key principle is that to move from a lower circular orbit to a higher circular orbit, a spacecraft must increase its velocity. This is achieved by firing its engines in the direction of motion, imparting an impulse that raises the apogee of its orbit. To circularize the orbit at the higher radius, a second impulse is required, again in the direction of motion, to increase the velocity at the new apogee to match the velocity of the higher circular orbit. Conversely, to move from a higher circular orbit to a lower one, the spacecraft must decrease its velocity, requiring retro-firings. The question asks about the most efficient method to *increase* the orbital altitude for a satellite in a stable circular orbit around Earth, as would be studied in aerospace engineering programs at Siberian State Aerospace University. This implies moving to a higher, larger orbit. Therefore, the most energy-efficient method, minimizing fuel consumption and thus maximizing payload or mission duration, involves two tangential burns. The first burn increases the velocity, raising the orbit’s apogee to the desired higher altitude. The second burn, performed at this new apogee, further increases the velocity to circularize the orbit at the higher altitude. This two-impulse maneuver is the hallmark of the Hohmann transfer, which is the most fuel-efficient way to transfer between two coplanar circular orbits. Other methods, like continuous low-thrust propulsion, can achieve the same transfer but are generally slower and require more complex trajectory planning, and while they might be considered for certain missions, the Hohmann transfer is the benchmark for efficiency in this context. A single tangential burn would result in an elliptical orbit, not a stable circular orbit at the new altitude. A radial burn would significantly alter the orbit’s shape and orientation but not efficiently increase its semi-major axis towards a higher circular orbit.
Incorrect
The question probes the understanding of orbital mechanics and the factors influencing spacecraft trajectory adjustments, specifically concerning the Hohmann transfer orbit. A Hohmann transfer is an elliptical orbit that connects two coplanar circular orbits of different radii. The key principle is that to move from a lower circular orbit to a higher circular orbit, a spacecraft must increase its velocity. This is achieved by firing its engines in the direction of motion, imparting an impulse that raises the apogee of its orbit. To circularize the orbit at the higher radius, a second impulse is required, again in the direction of motion, to increase the velocity at the new apogee to match the velocity of the higher circular orbit. Conversely, to move from a higher circular orbit to a lower one, the spacecraft must decrease its velocity, requiring retro-firings. The question asks about the most efficient method to *increase* the orbital altitude for a satellite in a stable circular orbit around Earth, as would be studied in aerospace engineering programs at Siberian State Aerospace University. This implies moving to a higher, larger orbit. Therefore, the most energy-efficient method, minimizing fuel consumption and thus maximizing payload or mission duration, involves two tangential burns. The first burn increases the velocity, raising the orbit’s apogee to the desired higher altitude. The second burn, performed at this new apogee, further increases the velocity to circularize the orbit at the higher altitude. This two-impulse maneuver is the hallmark of the Hohmann transfer, which is the most fuel-efficient way to transfer between two coplanar circular orbits. Other methods, like continuous low-thrust propulsion, can achieve the same transfer but are generally slower and require more complex trajectory planning, and while they might be considered for certain missions, the Hohmann transfer is the benchmark for efficiency in this context. A single tangential burn would result in an elliptical orbit, not a stable circular orbit at the new altitude. A radial burn would significantly alter the orbit’s shape and orientation but not efficiently increase its semi-major axis towards a higher circular orbit.
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Question 11 of 30
11. Question
A scientific probe, launched from Baikonur Cosmodrome, is currently maintaining a stable circular orbit around Earth at an altitude of 400 kilometers. The mission objectives necessitate its relocation to a higher circular orbit at an altitude of 1,200 kilometers. Considering the paramount importance of propellant conservation for extended deep-space exploration, which orbital transfer strategy would be the most judicious and energy-efficient approach for the Siberian State Aerospace University’s mission control to implement?
Correct
The question probes the understanding of orbital mechanics and the fundamental principles governing spacecraft trajectories, specifically concerning the energy required for orbital maneuvers. The scenario describes a spacecraft in a circular orbit around Earth and the objective is to transfer it to a higher circular orbit. This is achieved through a Hohmann transfer orbit, which is the most energy-efficient two-impulse maneuver for transferring between two coplanar circular orbits. The Hohmann transfer orbit is an ellipse that is tangent to both the initial and final circular orbits. The first impulse is applied at the periapsis of the transfer ellipse (tangent to the initial orbit), increasing the spacecraft’s velocity and energy to enter the elliptical transfer orbit. The second impulse is applied at the apoapsis of the transfer ellipse (tangent to the final orbit), increasing the spacecraft’s velocity again to circularize the orbit at the higher altitude. The energy required for such a transfer is directly related to the change in velocity (\(\Delta v\)) needed at each impulse. The total energy expenditure is the sum of the magnitudes of these velocity changes. While the question does not require explicit calculation of \(\Delta v\) values, it tests the conceptual understanding of which maneuver is most energy-efficient. Among the given options, a Hohmann transfer orbit is universally recognized as the most fuel-efficient method for such orbital transfers in the absence of gravitational assists or other advanced techniques. Other maneuvers, like a direct tangential burn to a higher circular orbit without an intermediate elliptical transfer, would require a significantly larger single impulse and thus more energy. Similarly, a bi-elliptic transfer, while potentially more efficient for very large orbital changes, involves three impulses and is generally less efficient for moderate altitude increases. A retrograde burn would decrease orbital energy, moving to a lower orbit, which is contrary to the objective. Therefore, the Hohmann transfer orbit represents the optimal strategy for minimizing propellant consumption, a critical consideration in space missions.
Incorrect
The question probes the understanding of orbital mechanics and the fundamental principles governing spacecraft trajectories, specifically concerning the energy required for orbital maneuvers. The scenario describes a spacecraft in a circular orbit around Earth and the objective is to transfer it to a higher circular orbit. This is achieved through a Hohmann transfer orbit, which is the most energy-efficient two-impulse maneuver for transferring between two coplanar circular orbits. The Hohmann transfer orbit is an ellipse that is tangent to both the initial and final circular orbits. The first impulse is applied at the periapsis of the transfer ellipse (tangent to the initial orbit), increasing the spacecraft’s velocity and energy to enter the elliptical transfer orbit. The second impulse is applied at the apoapsis of the transfer ellipse (tangent to the final orbit), increasing the spacecraft’s velocity again to circularize the orbit at the higher altitude. The energy required for such a transfer is directly related to the change in velocity (\(\Delta v\)) needed at each impulse. The total energy expenditure is the sum of the magnitudes of these velocity changes. While the question does not require explicit calculation of \(\Delta v\) values, it tests the conceptual understanding of which maneuver is most energy-efficient. Among the given options, a Hohmann transfer orbit is universally recognized as the most fuel-efficient method for such orbital transfers in the absence of gravitational assists or other advanced techniques. Other maneuvers, like a direct tangential burn to a higher circular orbit without an intermediate elliptical transfer, would require a significantly larger single impulse and thus more energy. Similarly, a bi-elliptic transfer, while potentially more efficient for very large orbital changes, involves three impulses and is generally less efficient for moderate altitude increases. A retrograde burn would decrease orbital energy, moving to a lower orbit, which is contrary to the objective. Therefore, the Hohmann transfer orbit represents the optimal strategy for minimizing propellant consumption, a critical consideration in space missions.
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Question 12 of 30
12. Question
Consider a satellite in a stable circular orbit around Earth. To initiate a transfer to a higher circular orbit using the most fuel-efficient method, what is the fundamental action the satellite’s propulsion system must perform at the point of departure from the initial orbit?
Correct
The question probes the understanding of orbital mechanics and the principles governing spacecraft trajectory adjustments, specifically focusing on the concept of a Hohmann transfer orbit. A Hohmann transfer is an elliptical orbit that connects two coplanar circular orbits of different radii. The key to this question lies in understanding that to move from a lower orbit to a higher orbit, a spacecraft must increase its velocity. This is achieved by firing its engines in the direction of motion, which imparts a tangential impulse. This impulse increases the spacecraft’s kinetic energy and alters its trajectory to an ellipse that is tangent to both the initial and final circular orbits. The higher apogee of this elliptical orbit allows it to reach the radius of the target orbit. Upon reaching the target orbit’s radius, a second tangential impulse, again in the direction of motion, is required to circularize the orbit at the higher altitude. This second burn increases the velocity further, matching the velocity required for the higher circular orbit. Therefore, to transition from a lower circular orbit to a higher circular orbit, two propulsive maneuvers are necessary: one to initiate the transfer ellipse and another to circularize at the destination. The question asks about the *initial* maneuver to *begin* the transition to a higher orbit. This initial maneuver involves increasing velocity tangentially to enter the transfer ellipse.
Incorrect
The question probes the understanding of orbital mechanics and the principles governing spacecraft trajectory adjustments, specifically focusing on the concept of a Hohmann transfer orbit. A Hohmann transfer is an elliptical orbit that connects two coplanar circular orbits of different radii. The key to this question lies in understanding that to move from a lower orbit to a higher orbit, a spacecraft must increase its velocity. This is achieved by firing its engines in the direction of motion, which imparts a tangential impulse. This impulse increases the spacecraft’s kinetic energy and alters its trajectory to an ellipse that is tangent to both the initial and final circular orbits. The higher apogee of this elliptical orbit allows it to reach the radius of the target orbit. Upon reaching the target orbit’s radius, a second tangential impulse, again in the direction of motion, is required to circularize the orbit at the higher altitude. This second burn increases the velocity further, matching the velocity required for the higher circular orbit. Therefore, to transition from a lower circular orbit to a higher circular orbit, two propulsive maneuvers are necessary: one to initiate the transfer ellipse and another to circularize at the destination. The question asks about the *initial* maneuver to *begin* the transition to a higher orbit. This initial maneuver involves increasing velocity tangentially to enter the transfer ellipse.
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Question 13 of 30
13. Question
Consider a scenario where a new experimental probe is being prepared for deployment from a launch platform orbiting Earth. The mission objective is to transition the probe into a geostationary transfer orbit (GTO) before it autonomously maneuvers to its final geostationary orbit. During the initial phase of this maneuver, what single parameter, if not precisely controlled, would most critically jeopardize the successful establishment of the intended orbital path, irrespective of the subsequent autonomous adjustments?
Correct
The question probes the understanding of orbital mechanics and the fundamental principles governing spacecraft trajectories, particularly in the context of achieving a stable orbit around a celestial body. To achieve a stable circular orbit at a specific altitude, a spacecraft must attain a precise tangential velocity. This velocity is determined by the gravitational force of the celestial body, which provides the centripetal force required to keep the spacecraft in orbit. The formula for orbital velocity \(v\) in a circular orbit is derived from equating the gravitational force \(F_g\) to the centripetal force \(F_c\): \[F_g = F_c\] \[\frac{GMm}{r^2} = \frac{mv^2}{r}\] where: \(G\) is the gravitational constant, \(M\) is the mass of the celestial body, \(m\) is the mass of the spacecraft, \(r\) is the orbital radius (distance from the center of the celestial body to the spacecraft), \(v\) is the orbital velocity. Solving for \(v\): \[v^2 = \frac{GM}{r}\] \[v = \sqrt{\frac{GM}{r}}\] The question asks about the *most critical* factor for achieving a stable orbit at a specific altitude, implying a need to consider the initial conditions and the fundamental requirement for orbital insertion. While other factors like atmospheric drag (if applicable), propulsion system efficiency, and navigation accuracy are important for *maintaining* an orbit or for *precise* orbital insertion, the *fundamental prerequisite* for establishing any stable orbit is achieving the correct tangential velocity. Without this velocity, the spacecraft will either escape the gravitational pull, fall back to the celestial body, or enter an elliptical/unstable trajectory. Therefore, the precise tangential velocity is the most critical factor for *achieving* a stable orbit at a given altitude. This concept is central to astrodynamics, a core discipline within aerospace engineering studied at Siberian State Aerospace University. Understanding this principle is vital for designing mission trajectories, whether for Earth-orbiting satellites or interplanetary probes, reflecting the university’s focus on practical space exploration and engineering.
Incorrect
The question probes the understanding of orbital mechanics and the fundamental principles governing spacecraft trajectories, particularly in the context of achieving a stable orbit around a celestial body. To achieve a stable circular orbit at a specific altitude, a spacecraft must attain a precise tangential velocity. This velocity is determined by the gravitational force of the celestial body, which provides the centripetal force required to keep the spacecraft in orbit. The formula for orbital velocity \(v\) in a circular orbit is derived from equating the gravitational force \(F_g\) to the centripetal force \(F_c\): \[F_g = F_c\] \[\frac{GMm}{r^2} = \frac{mv^2}{r}\] where: \(G\) is the gravitational constant, \(M\) is the mass of the celestial body, \(m\) is the mass of the spacecraft, \(r\) is the orbital radius (distance from the center of the celestial body to the spacecraft), \(v\) is the orbital velocity. Solving for \(v\): \[v^2 = \frac{GM}{r}\] \[v = \sqrt{\frac{GM}{r}}\] The question asks about the *most critical* factor for achieving a stable orbit at a specific altitude, implying a need to consider the initial conditions and the fundamental requirement for orbital insertion. While other factors like atmospheric drag (if applicable), propulsion system efficiency, and navigation accuracy are important for *maintaining* an orbit or for *precise* orbital insertion, the *fundamental prerequisite* for establishing any stable orbit is achieving the correct tangential velocity. Without this velocity, the spacecraft will either escape the gravitational pull, fall back to the celestial body, or enter an elliptical/unstable trajectory. Therefore, the precise tangential velocity is the most critical factor for *achieving* a stable orbit at a given altitude. This concept is central to astrodynamics, a core discipline within aerospace engineering studied at Siberian State Aerospace University. Understanding this principle is vital for designing mission trajectories, whether for Earth-orbiting satellites or interplanetary probes, reflecting the university’s focus on practical space exploration and engineering.
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Question 14 of 30
14. Question
Consider a scenario where a probe is to be moved from a low Earth orbit to a higher, circular geostationary orbit. To minimize the propellant expenditure for this orbital maneuver, which of the following trajectory adjustments, assuming coplanar orbits and two distinct propulsive burns, would be the most energetically efficient approach for the Siberian State Aerospace University’s mission planners?
Correct
The question probes the understanding of orbital mechanics and the principles governing spacecraft trajectory adjustments, specifically concerning the Hohmann transfer orbit. A Hohmann transfer is an elliptical orbit used to transfer between two circular orbits of different altitudes in the same plane. The efficiency of this transfer is paramount in mission planning to minimize fuel consumption. The core concept here is that a Hohmann transfer is the most fuel-efficient two-impulse maneuver for transferring between coplanar circular orbits. While other transfer orbits exist (e.g., bi-elliptic transfers), they are generally more fuel-intensive for typical interplanetary distances and require more impulses. The question asks about the *most fuel-efficient* method for such a transfer, directly pointing to the Hohmann transfer’s optimality under these conditions. The explanation should emphasize that this optimality stems from minimizing the total change in velocity (\(\Delta v\)) required for the transfer. The calculation, while not numerical, involves understanding that the Hohmann transfer achieves this by using tangential burns at the periapsis and apoapsis of the transfer ellipse, which are the most efficient points to alter orbital energy. Therefore, any deviation from this specific elliptical path, or the use of non-tangential burns, would inherently increase the required \(\Delta v\) and thus fuel expenditure. The explanation should also touch upon the trade-offs, such as longer transfer times compared to faster, less efficient trajectories, which is a critical consideration in mission design at institutions like Siberian State Aerospace University.
Incorrect
The question probes the understanding of orbital mechanics and the principles governing spacecraft trajectory adjustments, specifically concerning the Hohmann transfer orbit. A Hohmann transfer is an elliptical orbit used to transfer between two circular orbits of different altitudes in the same plane. The efficiency of this transfer is paramount in mission planning to minimize fuel consumption. The core concept here is that a Hohmann transfer is the most fuel-efficient two-impulse maneuver for transferring between coplanar circular orbits. While other transfer orbits exist (e.g., bi-elliptic transfers), they are generally more fuel-intensive for typical interplanetary distances and require more impulses. The question asks about the *most fuel-efficient* method for such a transfer, directly pointing to the Hohmann transfer’s optimality under these conditions. The explanation should emphasize that this optimality stems from minimizing the total change in velocity (\(\Delta v\)) required for the transfer. The calculation, while not numerical, involves understanding that the Hohmann transfer achieves this by using tangential burns at the periapsis and apoapsis of the transfer ellipse, which are the most efficient points to alter orbital energy. Therefore, any deviation from this specific elliptical path, or the use of non-tangential burns, would inherently increase the required \(\Delta v\) and thus fuel expenditure. The explanation should also touch upon the trade-offs, such as longer transfer times compared to faster, less efficient trajectories, which is a critical consideration in mission design at institutions like Siberian State Aerospace University.
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Question 15 of 30
15. Question
Consider a hypothetical unpowered descent module from Siberian State Aerospace University’s experimental orbital platform. As this module enters the Earth’s atmosphere at hypersonic velocity, what is the predominant physical process responsible for the rapid dissipation of its substantial kinetic energy, leading to its deceleration and eventual thermal load?
Correct
The question probes the understanding of fundamental principles in orbital mechanics and atmospheric reentry, specifically concerning the energy dissipation mechanisms that govern a spacecraft’s descent. During atmospheric reentry, a spacecraft experiences significant aerodynamic drag. This drag force acts opposite to the direction of motion, converting the spacecraft’s kinetic energy into heat. The rate at which this energy is dissipated is directly related to the drag coefficient (\(C_d\)), the atmospheric density (\(\rho\)), the spacecraft’s velocity (\(v\)), and its reference area (\(A\)). The drag force is given by \(F_d = \frac{1}{2} \rho v^2 C_d A\). The power dissipated by drag is \(P_d = F_d \cdot v = \frac{1}{2} \rho v^3 C_d A\). The primary mechanism for energy loss during reentry is not radiative cooling of the spacecraft’s structure itself, nor is it the work done by onboard thrusters (which are typically inactive or used for minor adjustments during the main reentry phase). While thermal management systems are crucial for protecting the spacecraft, they are a consequence of the energy dissipation, not the primary cause of it. Similarly, the gravitational potential energy loss contributes to the overall energy change, but the *rate* of energy dissipation, which dictates the heating profile and deceleration, is overwhelmingly dominated by aerodynamic drag. Therefore, the most significant factor in the rapid decrease of kinetic energy during atmospheric entry is the conversion of this kinetic energy into thermal energy through aerodynamic drag. This process is fundamental to understanding reentry trajectories and thermal protection system design, core areas of study at Siberian State Aerospace University.
Incorrect
The question probes the understanding of fundamental principles in orbital mechanics and atmospheric reentry, specifically concerning the energy dissipation mechanisms that govern a spacecraft’s descent. During atmospheric reentry, a spacecraft experiences significant aerodynamic drag. This drag force acts opposite to the direction of motion, converting the spacecraft’s kinetic energy into heat. The rate at which this energy is dissipated is directly related to the drag coefficient (\(C_d\)), the atmospheric density (\(\rho\)), the spacecraft’s velocity (\(v\)), and its reference area (\(A\)). The drag force is given by \(F_d = \frac{1}{2} \rho v^2 C_d A\). The power dissipated by drag is \(P_d = F_d \cdot v = \frac{1}{2} \rho v^3 C_d A\). The primary mechanism for energy loss during reentry is not radiative cooling of the spacecraft’s structure itself, nor is it the work done by onboard thrusters (which are typically inactive or used for minor adjustments during the main reentry phase). While thermal management systems are crucial for protecting the spacecraft, they are a consequence of the energy dissipation, not the primary cause of it. Similarly, the gravitational potential energy loss contributes to the overall energy change, but the *rate* of energy dissipation, which dictates the heating profile and deceleration, is overwhelmingly dominated by aerodynamic drag. Therefore, the most significant factor in the rapid decrease of kinetic energy during atmospheric entry is the conversion of this kinetic energy into thermal energy through aerodynamic drag. This process is fundamental to understanding reentry trajectories and thermal protection system design, core areas of study at Siberian State Aerospace University.
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Question 16 of 30
16. Question
Consider a scenario where a newly deployed observation satellite for the Siberian State Aerospace University’s Earth observation program is initially placed in a highly elliptical transfer orbit. To transition this satellite into a stable, near-circular operational orbit at a significantly higher altitude, what fundamental principle must the satellite’s propulsion system precisely adhere to during the orbital insertion burn?
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The question probes the understanding of orbital mechanics and the fundamental principles governing satellite trajectories, particularly in the context of achieving a stable orbit around a celestial body. To achieve a stable orbit, a satellite must possess a specific tangential velocity that precisely balances the gravitational pull of the celestial body at a given altitude. This balance prevents the satellite from either falling back to the celestial body or escaping its gravitational influence. The required velocity is not arbitrary but is determined by the mass of the celestial body and the radius of the orbit. For a circular orbit, the centripetal force required to keep the satellite in its path is provided by the gravitational force. This relationship can be expressed as: \[ \frac{mv^2}{r} = \frac{GMm}{r^2} \] where: \(m\) is the mass of the satellite \(v\) is the orbital velocity of the satellite \(r\) is the orbital radius (distance from the center of the celestial body to the satellite) \(G\) is the gravitational constant \(M\) is the mass of the celestial body Simplifying this equation to solve for \(v\), we get: \[ v^2 = \frac{GM}{r} \] \[ v = \sqrt{\frac{GM}{r}} \] This formula indicates that the orbital velocity is inversely proportional to the square root of the orbital radius. Therefore, to maintain a stable orbit at a higher altitude (larger \(r\)), a lower tangential velocity is required. Conversely, a lower altitude (smaller \(r\)) necessitates a higher tangential velocity. The question implicitly asks about the conditions for maintaining a stable orbit, which is achieved when the tangential velocity is precisely matched to the gravitational force at that altitude. Any significant deviation from this velocity would result in a change in the orbital path, potentially leading to a decay or escape. The concept of achieving a stable orbit is a cornerstone of aerospace engineering and is fundamental to the operations of satellites and spacecraft, a key area of study at Siberian State Aerospace University. Understanding this relationship is crucial for mission planning, trajectory design, and ensuring the longevity of space missions.
Incorrect
The question probes the understanding of orbital mechanics and the fundamental principles governing satellite trajectories, particularly in the context of achieving a stable orbit around a celestial body. To achieve a stable orbit, a satellite must possess a specific tangential velocity that precisely balances the gravitational pull of the celestial body at a given altitude. This balance prevents the satellite from either falling back to the celestial body or escaping its gravitational influence. The required velocity is not arbitrary but is determined by the mass of the celestial body and the radius of the orbit. For a circular orbit, the centripetal force required to keep the satellite in its path is provided by the gravitational force. This relationship can be expressed as: \[ \frac{mv^2}{r} = \frac{GMm}{r^2} \] where: \(m\) is the mass of the satellite \(v\) is the orbital velocity of the satellite \(r\) is the orbital radius (distance from the center of the celestial body to the satellite) \(G\) is the gravitational constant \(M\) is the mass of the celestial body Simplifying this equation to solve for \(v\), we get: \[ v^2 = \frac{GM}{r} \] \[ v = \sqrt{\frac{GM}{r}} \] This formula indicates that the orbital velocity is inversely proportional to the square root of the orbital radius. Therefore, to maintain a stable orbit at a higher altitude (larger \(r\)), a lower tangential velocity is required. Conversely, a lower altitude (smaller \(r\)) necessitates a higher tangential velocity. The question implicitly asks about the conditions for maintaining a stable orbit, which is achieved when the tangential velocity is precisely matched to the gravitational force at that altitude. Any significant deviation from this velocity would result in a change in the orbital path, potentially leading to a decay or escape. The concept of achieving a stable orbit is a cornerstone of aerospace engineering and is fundamental to the operations of satellites and spacecraft, a key area of study at Siberian State Aerospace University. Understanding this relationship is crucial for mission planning, trajectory design, and ensuring the longevity of space missions.
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Question 17 of 30
17. Question
A spacecraft is currently in a circular orbit around Earth at an altitude of 300 km. Mission planners at Siberian State Aerospace University aim to transfer this spacecraft to a higher circular orbit at an altitude of 1000 km. Considering the principles of orbital mechanics and the need for fuel efficiency in interplanetary missions, which of the following orbital transfer strategies would represent the most energy-efficient method to achieve this orbital change, and what is the approximate total velocity change required for this maneuver?
Correct
The question probes the understanding of orbital mechanics and the factors influencing satellite trajectory adjustments, specifically concerning the conservation of angular momentum and the energy changes associated with orbital maneuvers. A Hohmann transfer orbit is the most energy-efficient two-impulse maneuver for transferring between two coplanar circular orbits. The first impulse increases the spacecraft’s velocity, injecting it into an elliptical transfer orbit whose periapsis is tangent to the initial circular orbit and whose apoapsis is tangent to the target circular orbit. The second impulse, applied at the apoapsis of the transfer orbit, increases the velocity again to circularize the orbit at the higher altitude. To calculate the required velocity changes, we consider the vis-viva equation, \(v = \sqrt{\mu(\frac{2}{r} – \frac{1}{a})}\), where \(v\) is the orbital velocity, \(\mu\) is the standard gravitational parameter of the central body (Earth, in this case, \(\mu_{Earth} \approx 3.986 \times 10^{14} \, \text{m}^3/\text{s}^2\)), \(r\) is the current distance from the central body, and \(a\) is the semi-major axis of the orbit. For the initial circular orbit at altitude \(h_1 = 300 \, \text{km}\) above Earth’s surface, the orbital radius is \(r_1 = R_{Earth} + h_1 = 6371 \, \text{km} + 300 \, \text{km} = 6671 \, \text{km} = 6.671 \times 10^6 \, \text{m}\). The velocity in this circular orbit is \(v_1 = \sqrt{\frac{\mu}{r_1}}\). For the target circular orbit at altitude \(h_2 = 1000 \, \text{km}\), the orbital radius is \(r_2 = R_{Earth} + h_2 = 6371 \, \text{km} + 1000 \, \text{km} = 7371 \, \text{km} = 7.371 \times 10^6 \, \text{m}\). The velocity in this circular orbit is \(v_2 = \sqrt{\frac{\mu}{r_2}}\). The Hohmann transfer orbit has a semi-major axis \(a_{transfer} = \frac{r_1 + r_2}{2} = \frac{6.671 \times 10^6 \, \text{m} + 7.371 \times 10^6 \, \text{m}}{2} = 7.021 \times 10^6 \, \text{m}\). The velocity at periapsis of the transfer orbit (which is \(v_1’\) for the maneuver) is \(v_1′ = \sqrt{\mu(\frac{2}{r_1} – \frac{1}{a_{transfer}})}\). The velocity at apoapsis of the transfer orbit (which is \(v_2’\) for the maneuver) is \(v_2′ = \sqrt{\mu(\frac{2}{r_2} – \frac{1}{a_{transfer}})}\). The first velocity change required is \(\Delta v_1 = v_1′ – v_1\). The second velocity change required is \(\Delta v_2 = v_2 – v_2’\). Let’s calculate these values: \(\mu = 3.986 \times 10^{14} \, \text{m}^3/\text{s}^2\) \(r_1 = 6.671 \times 10^6 \, \text{m}\) \(r_2 = 7.371 \times 10^6 \, \text{m}\) \(a_{transfer} = 7.021 \times 10^6 \, \text{m}\) \(v_1 = \sqrt{\frac{3.986 \times 10^{14}}{6.671 \times 10^6}} \approx \sqrt{5.975 \times 10^7} \approx 7730 \, \text{m/s}\) \(v_1′ = \sqrt{3.986 \times 10^{14} (\frac{2}{6.671 \times 10^6} – \frac{1}{7.021 \times 10^6})} \approx \sqrt{3.986 \times 10^{14} (2.998 \times 10^{-7} – 1.424 \times 10^{-7})} \approx \sqrt{3.986 \times 10^{14} (1.574 \times 10^{-7})} \approx \sqrt{6.276 \times 10^7} \approx 7922 \, \text{m/s}\) \(\Delta v_1 = 7922 – 7730 = 192 \, \text{m/s}\) \(v_2′ = \sqrt{3.986 \times 10^{14} (\frac{2}{7.371 \times 10^6} – \frac{1}{7.021 \times 10^6})} \approx \sqrt{3.986 \times 10^{14} (2.714 \times 10^{-7} – 1.424 \times 10^{-7})} \approx \sqrt{3.986 \times 10^{14} (1.290 \times 10^{-7})} \approx \sqrt{5.142 \times 10^7} \approx 7171 \, \text{m/s}\) \(v_2 = \sqrt{\frac{3.986 \times 10^{14}}{7.371 \times 10^6}} \approx \sqrt{5.407 \times 10^7} \approx 7353 \, \text{m/s}\) \(\Delta v_2 = 7353 – 7171 = 182 \, \text{m/s}\) The total \(\Delta v\) for a Hohmann transfer is \(\Delta v_{total} = \Delta v_1 + \Delta v_2 = 192 \, \text{m/s} + 182 \, \text{m/s} = 374 \, \text{m/s}\). The question asks about the most efficient method for a spacecraft departing from a low Earth orbit (LEO) to a higher circular orbit, considering the principles of orbital mechanics taught at Siberian State Aerospace University. The most energy-efficient transfer between two coplanar circular orbits is the Hohmann transfer orbit. This maneuver involves two impulsive burns. The first burn increases the spacecraft’s velocity to enter an elliptical transfer orbit, and the second burn at the apoapsis of the transfer orbit circularizes the orbit at the higher altitude. The efficiency of this transfer is due to its minimal total velocity change (\(\Delta v\)), which directly translates to less propellant consumption. Understanding the trade-offs between transfer time and propellant usage is crucial in mission design. While faster transfers exist (e.g., bi-elliptic transfers or continuous thrust trajectories), they generally require significantly more \(\Delta v\). The Hohmann transfer represents a fundamental concept in astrodynamics, emphasizing the conservation of energy and angular momentum in orbital maneuvers. Students at Siberian State Aerospace University would be expected to grasp these principles to design and analyze space missions, considering factors like fuel efficiency, mission duration, and the gravitational influences of celestial bodies. The calculation demonstrates that the total velocity change for this specific transfer is approximately 374 m/s, highlighting the precise calculations required for successful orbital insertions.
Incorrect
The question probes the understanding of orbital mechanics and the factors influencing satellite trajectory adjustments, specifically concerning the conservation of angular momentum and the energy changes associated with orbital maneuvers. A Hohmann transfer orbit is the most energy-efficient two-impulse maneuver for transferring between two coplanar circular orbits. The first impulse increases the spacecraft’s velocity, injecting it into an elliptical transfer orbit whose periapsis is tangent to the initial circular orbit and whose apoapsis is tangent to the target circular orbit. The second impulse, applied at the apoapsis of the transfer orbit, increases the velocity again to circularize the orbit at the higher altitude. To calculate the required velocity changes, we consider the vis-viva equation, \(v = \sqrt{\mu(\frac{2}{r} – \frac{1}{a})}\), where \(v\) is the orbital velocity, \(\mu\) is the standard gravitational parameter of the central body (Earth, in this case, \(\mu_{Earth} \approx 3.986 \times 10^{14} \, \text{m}^3/\text{s}^2\)), \(r\) is the current distance from the central body, and \(a\) is the semi-major axis of the orbit. For the initial circular orbit at altitude \(h_1 = 300 \, \text{km}\) above Earth’s surface, the orbital radius is \(r_1 = R_{Earth} + h_1 = 6371 \, \text{km} + 300 \, \text{km} = 6671 \, \text{km} = 6.671 \times 10^6 \, \text{m}\). The velocity in this circular orbit is \(v_1 = \sqrt{\frac{\mu}{r_1}}\). For the target circular orbit at altitude \(h_2 = 1000 \, \text{km}\), the orbital radius is \(r_2 = R_{Earth} + h_2 = 6371 \, \text{km} + 1000 \, \text{km} = 7371 \, \text{km} = 7.371 \times 10^6 \, \text{m}\). The velocity in this circular orbit is \(v_2 = \sqrt{\frac{\mu}{r_2}}\). The Hohmann transfer orbit has a semi-major axis \(a_{transfer} = \frac{r_1 + r_2}{2} = \frac{6.671 \times 10^6 \, \text{m} + 7.371 \times 10^6 \, \text{m}}{2} = 7.021 \times 10^6 \, \text{m}\). The velocity at periapsis of the transfer orbit (which is \(v_1’\) for the maneuver) is \(v_1′ = \sqrt{\mu(\frac{2}{r_1} – \frac{1}{a_{transfer}})}\). The velocity at apoapsis of the transfer orbit (which is \(v_2’\) for the maneuver) is \(v_2′ = \sqrt{\mu(\frac{2}{r_2} – \frac{1}{a_{transfer}})}\). The first velocity change required is \(\Delta v_1 = v_1′ – v_1\). The second velocity change required is \(\Delta v_2 = v_2 – v_2’\). Let’s calculate these values: \(\mu = 3.986 \times 10^{14} \, \text{m}^3/\text{s}^2\) \(r_1 = 6.671 \times 10^6 \, \text{m}\) \(r_2 = 7.371 \times 10^6 \, \text{m}\) \(a_{transfer} = 7.021 \times 10^6 \, \text{m}\) \(v_1 = \sqrt{\frac{3.986 \times 10^{14}}{6.671 \times 10^6}} \approx \sqrt{5.975 \times 10^7} \approx 7730 \, \text{m/s}\) \(v_1′ = \sqrt{3.986 \times 10^{14} (\frac{2}{6.671 \times 10^6} – \frac{1}{7.021 \times 10^6})} \approx \sqrt{3.986 \times 10^{14} (2.998 \times 10^{-7} – 1.424 \times 10^{-7})} \approx \sqrt{3.986 \times 10^{14} (1.574 \times 10^{-7})} \approx \sqrt{6.276 \times 10^7} \approx 7922 \, \text{m/s}\) \(\Delta v_1 = 7922 – 7730 = 192 \, \text{m/s}\) \(v_2′ = \sqrt{3.986 \times 10^{14} (\frac{2}{7.371 \times 10^6} – \frac{1}{7.021 \times 10^6})} \approx \sqrt{3.986 \times 10^{14} (2.714 \times 10^{-7} – 1.424 \times 10^{-7})} \approx \sqrt{3.986 \times 10^{14} (1.290 \times 10^{-7})} \approx \sqrt{5.142 \times 10^7} \approx 7171 \, \text{m/s}\) \(v_2 = \sqrt{\frac{3.986 \times 10^{14}}{7.371 \times 10^6}} \approx \sqrt{5.407 \times 10^7} \approx 7353 \, \text{m/s}\) \(\Delta v_2 = 7353 – 7171 = 182 \, \text{m/s}\) The total \(\Delta v\) for a Hohmann transfer is \(\Delta v_{total} = \Delta v_1 + \Delta v_2 = 192 \, \text{m/s} + 182 \, \text{m/s} = 374 \, \text{m/s}\). The question asks about the most efficient method for a spacecraft departing from a low Earth orbit (LEO) to a higher circular orbit, considering the principles of orbital mechanics taught at Siberian State Aerospace University. The most energy-efficient transfer between two coplanar circular orbits is the Hohmann transfer orbit. This maneuver involves two impulsive burns. The first burn increases the spacecraft’s velocity to enter an elliptical transfer orbit, and the second burn at the apoapsis of the transfer orbit circularizes the orbit at the higher altitude. The efficiency of this transfer is due to its minimal total velocity change (\(\Delta v\)), which directly translates to less propellant consumption. Understanding the trade-offs between transfer time and propellant usage is crucial in mission design. While faster transfers exist (e.g., bi-elliptic transfers or continuous thrust trajectories), they generally require significantly more \(\Delta v\). The Hohmann transfer represents a fundamental concept in astrodynamics, emphasizing the conservation of energy and angular momentum in orbital maneuvers. Students at Siberian State Aerospace University would be expected to grasp these principles to design and analyze space missions, considering factors like fuel efficiency, mission duration, and the gravitational influences of celestial bodies. The calculation demonstrates that the total velocity change for this specific transfer is approximately 374 m/s, highlighting the precise calculations required for successful orbital insertions.
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Question 18 of 30
18. Question
A communication satellite positioned in a geostationary orbit above the equator for the Siberian State Aerospace University Entrance Exam’s ground tracking station is observed to be drifting westward relative to its intended longitude. To counteract this drift and re-establish its precise orbital position, what is the most effective type of orbital maneuver to implement, considering the fundamental principles of celestial mechanics and the operational constraints of such a satellite?
Correct
The question probes the understanding of orbital mechanics and the factors influencing satellite trajectory adjustments, specifically in the context of maintaining a stable geostationary orbit. A geostationary orbit is a specific type of geosynchronous orbit, directly above the Earth’s equator, that remains in a fixed position relative to a particular point on the ground. Satellites in geostationary orbit are subject to various perturbing forces. The primary forces that cause deviations from the ideal geostationary position are the gravitational pull of the Moon and the Sun, and the Earth’s oblateness (its equatorial bulge). These forces create a slight drift in the satellite’s longitude. To counteract these drifts and maintain the satellite’s position over its designated ground station, periodic station-keeping maneuvers are required. These maneuvers involve firing small thrusters to impart a change in velocity, thereby correcting the orbital parameters. The most efficient way to correct for longitudinal drift in a geostationary orbit is by applying a tangential thrust. A tangential thrust, applied in the direction of motion, will increase the satellite’s orbital speed. This increased speed will cause the satellite to move to a slightly higher orbit, which has a longer orbital period. Consequently, the satellite will appear to drift westward relative to the Earth’s surface. Conversely, a thrust applied opposite to the direction of motion will decrease the orbital speed, causing the satellite to move to a lower orbit with a shorter orbital period, appearing to drift eastward. Therefore, to correct a westward drift (which is the typical drift caused by luni-solar perturbations), a thrust must be applied *opposite* to the direction of motion to slow the satellite down, causing it to fall into a slightly lower orbit and thus appear to drift eastward, effectively counteracting the westward drift.
Incorrect
The question probes the understanding of orbital mechanics and the factors influencing satellite trajectory adjustments, specifically in the context of maintaining a stable geostationary orbit. A geostationary orbit is a specific type of geosynchronous orbit, directly above the Earth’s equator, that remains in a fixed position relative to a particular point on the ground. Satellites in geostationary orbit are subject to various perturbing forces. The primary forces that cause deviations from the ideal geostationary position are the gravitational pull of the Moon and the Sun, and the Earth’s oblateness (its equatorial bulge). These forces create a slight drift in the satellite’s longitude. To counteract these drifts and maintain the satellite’s position over its designated ground station, periodic station-keeping maneuvers are required. These maneuvers involve firing small thrusters to impart a change in velocity, thereby correcting the orbital parameters. The most efficient way to correct for longitudinal drift in a geostationary orbit is by applying a tangential thrust. A tangential thrust, applied in the direction of motion, will increase the satellite’s orbital speed. This increased speed will cause the satellite to move to a slightly higher orbit, which has a longer orbital period. Consequently, the satellite will appear to drift westward relative to the Earth’s surface. Conversely, a thrust applied opposite to the direction of motion will decrease the orbital speed, causing the satellite to move to a lower orbit with a shorter orbital period, appearing to drift eastward. Therefore, to correct a westward drift (which is the typical drift caused by luni-solar perturbations), a thrust must be applied *opposite* to the direction of motion to slow the satellite down, causing it to fall into a slightly lower orbit and thus appear to drift eastward, effectively counteracting the westward drift.
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Question 19 of 30
19. Question
Consider a hypothetical mission by the Siberian State Aerospace University to place a research satellite into a higher energy orbit around the Earth, transitioning from a circular low Earth orbit to an elliptical orbit with a significantly larger apogee. To achieve this orbital insertion, a precisely timed propulsive burn will be executed. Which of the following factors is the most critical determinant of the total propellant mass required for this maneuver, assuming all other engine parameters remain constant?
Correct
The question probes the understanding of orbital mechanics and the fundamental principles governing spacecraft trajectories, specifically focusing on the concept of orbital insertion and the energy changes involved. A spacecraft in a transfer orbit, such as a Hohmann transfer, requires a propulsive burn to transition from one orbit to another. To move from a lower energy orbit to a higher energy orbit (e.g., from Earth orbit to a lunar transfer orbit), the spacecraft must increase its velocity. This increase in velocity requires expending propellant, which has mass. According to the Tsiolkovsky rocket equation, \(\Delta v = v_e \ln \frac{m_0}{m_f}\), where \(\Delta v\) is the change in velocity, \(v_e\) is the effective exhaust velocity, \(m_0\) is the initial mass, and \(m_f\) is the final mass. A higher \(\Delta v\) requirement, or a more efficient engine (higher \(v_e\)), leads to a greater propellant mass fraction. For a mission originating from Earth and targeting a lunar orbit, the required \(\Delta v\) for the trans-lunar injection (TLI) burn is substantial. This burn increases the spacecraft’s kinetic and potential energy, allowing it to escape Earth’s gravitational influence and reach the vicinity of the Moon. The efficiency of this maneuver is directly tied to the engine’s specific impulse and the mass ratio of the rocket. Therefore, the primary factor influencing the propellant required for such an orbital insertion maneuver is the magnitude of the velocity change needed to achieve the desired trajectory, which is dictated by orbital mechanics and the specific mission profile. The question tests the understanding that achieving a higher energy orbit necessitates a significant velocity increase, which in turn dictates the propellant mass.
Incorrect
The question probes the understanding of orbital mechanics and the fundamental principles governing spacecraft trajectories, specifically focusing on the concept of orbital insertion and the energy changes involved. A spacecraft in a transfer orbit, such as a Hohmann transfer, requires a propulsive burn to transition from one orbit to another. To move from a lower energy orbit to a higher energy orbit (e.g., from Earth orbit to a lunar transfer orbit), the spacecraft must increase its velocity. This increase in velocity requires expending propellant, which has mass. According to the Tsiolkovsky rocket equation, \(\Delta v = v_e \ln \frac{m_0}{m_f}\), where \(\Delta v\) is the change in velocity, \(v_e\) is the effective exhaust velocity, \(m_0\) is the initial mass, and \(m_f\) is the final mass. A higher \(\Delta v\) requirement, or a more efficient engine (higher \(v_e\)), leads to a greater propellant mass fraction. For a mission originating from Earth and targeting a lunar orbit, the required \(\Delta v\) for the trans-lunar injection (TLI) burn is substantial. This burn increases the spacecraft’s kinetic and potential energy, allowing it to escape Earth’s gravitational influence and reach the vicinity of the Moon. The efficiency of this maneuver is directly tied to the engine’s specific impulse and the mass ratio of the rocket. Therefore, the primary factor influencing the propellant required for such an orbital insertion maneuver is the magnitude of the velocity change needed to achieve the desired trajectory, which is dictated by orbital mechanics and the specific mission profile. The question tests the understanding that achieving a higher energy orbit necessitates a significant velocity increase, which in turn dictates the propellant mass.
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Question 20 of 30
20. Question
Consider a scenario where a newly designed orbital transfer vehicle, developed by engineers at Siberian State Aerospace University, is tasked with moving a satellite from a low Earth orbit to a higher, geostationary transfer orbit. The mission parameters dictate that fuel consumption must be minimized, and the transfer should be completed within a reasonable timeframe, avoiding excessively long transit periods. Which of the following orbital maneuver strategies would be considered the most fuel-efficient for achieving this specific type of orbital change, assuming impulsive burns and coplanar orbits?
Correct
The question probes the understanding of orbital mechanics and the principles governing spacecraft trajectory adjustments, specifically focusing on the efficiency of different propulsive maneuvers. The concept of delta-v (\(\Delta v\)) is central here, representing the change in velocity required for a maneuver. For a Hohmann transfer orbit, which is the most fuel-efficient two-impulse maneuver for transferring between two circular coplanar orbits, the total \(\Delta v\) is the sum of the \(\Delta v\) required to leave the initial orbit and the \(\Delta v\) required to enter the final orbit. Let \(r_1\) be the radius of the initial circular orbit and \(r_2\) be the radius of the final circular orbit. The velocity in the initial circular orbit is \(v_1 = \sqrt{\frac{\mu}{r_1}}\), where \(\mu\) is the standard gravitational parameter of the central body. The velocity at the periapsis of the transfer ellipse (at radius \(r_1\)) is \(v_{p,transfer} = \sqrt{\mu \left(\frac{2}{r_1} – \frac{1}{a_{transfer}}\right)}\), where \(a_{transfer} = \frac{r_1 + r_2}{2}\) is the semi-major axis of the transfer ellipse. The first \(\Delta v\) is \(\Delta v_1 = v_{p,transfer} – v_1\). The velocity at the apoapsis of the transfer ellipse (at radius \(r_2\)) is \(v_{a,transfer} = \sqrt{\mu \left(\frac{2}{r_2} – \frac{1}{a_{transfer}}\right)}\). The velocity in the final circular orbit is \(v_2 = \sqrt{\frac{\mu}{r_2}}\). The second \(\Delta v\) is \(\Delta v_2 = v_2 – v_{a,transfer}\). The total \(\Delta v\) for a Hohmann transfer is \(\Delta v_{total} = \Delta v_1 + \Delta v_2\). Consider a scenario where a spacecraft is in a circular orbit around Earth at an altitude of 300 km and needs to transfer to a circular orbit at an altitude of 1000 km. Given: Radius of Earth \(R_E \approx 6371\) km Standard gravitational parameter of Earth \(\mu \approx 3.986 \times 10^5\) km\(^3\)/s\(^2\) Initial orbit radius \(r_1 = R_E + 300 \text{ km} = 6371 + 300 = 6671\) km Final orbit radius \(r_2 = R_E + 1000 \text{ km} = 6371 + 1000 = 7371\) km Initial circular velocity \(v_1 = \sqrt{\frac{\mu}{r_1}} = \sqrt{\frac{3.986 \times 10^5}{6671}} \approx \sqrt{59.75} \approx 7.73\) km/s Semi-major axis of transfer ellipse \(a_{transfer} = \frac{r_1 + r_2}{2} = \frac{6671 + 7371}{2} = \frac{14042}{2} = 7021\) km Velocity at periapsis of transfer ellipse \(v_{p,transfer} = \sqrt{\mu \left(\frac{2}{r_1} – \frac{1}{a_{transfer}}\right)} = \sqrt{3.986 \times 10^5 \left(\frac{2}{6671} – \frac{1}{7021}\right)}\) \(v_{p,transfer} = \sqrt{3.986 \times 10^5 \left(0.0002998 – 0.0001424\right)} = \sqrt{3.986 \times 10^5 \times 0.0001574} \approx \sqrt{62.74} \approx 7.92\) km/s First \(\Delta v_1 = v_{p,transfer} – v_1 \approx 7.92 – 7.73 = 0.19\) km/s Velocity at apoapsis of transfer ellipse \(v_{a,transfer} = \sqrt{\mu \left(\frac{2}{r_2} – \frac{1}{a_{transfer}}\right)} = \sqrt{3.986 \times 10^5 \left(\frac{2}{7371} – \frac{1}{7021}\right)}\) \(v_{a,transfer} = \sqrt{3.986 \times 10^5 \left(0.0002713 – 0.0001424\right)} = \sqrt{3.986 \times 10^5 \times 0.0001289} \approx \sqrt{51.38} \approx 7.17\) km/s Final circular velocity \(v_2 = \sqrt{\frac{\mu}{r_2}} = \sqrt{\frac{3.986 \times 10^5}{7371}} \approx \sqrt{54.07} \approx 7.35\) km/s Second \(\Delta v_2 = v_2 – v_{a,transfer} \approx 7.35 – 7.17 = 0.18\) km/s Total \(\Delta v_{total} = \Delta v_1 + \Delta v_2 \approx 0.19 + 0.18 = 0.37\) km/s. The question asks about the *efficiency* of maneuvers. While Hohmann transfers are generally the most fuel-efficient for coplanar transfers, other maneuvers exist. Bi-elliptic transfers, for instance, can be more efficient for large changes in orbital radius, especially when the ratio of final to initial radius is very high. However, they require more impulses and longer transfer times. For moderate changes in orbital radius, as implied by the typical context of such problems, the Hohmann transfer remains a benchmark for efficiency. The question is designed to test the understanding of the fundamental trade-offs in orbital maneuvers: fuel efficiency versus time of flight and complexity of execution. The most fuel-efficient method for a single plane change and orbit adjustment between two circular orbits is typically the Hohmann transfer, which minimizes the total \(\Delta v\). Other methods, like continuous thrust or low-thrust trajectories, might achieve the same change in velocity but over a much longer period and with different efficiency considerations related to specific impulse and engine type. However, within the context of impulsive maneuvers, the Hohmann transfer is the standard for minimal \(\Delta v\). Therefore, understanding the principles behind it and its comparative efficiency is crucial for aerospace engineering students at Siberian State Aerospace University. The calculation above demonstrates the minimal \(\Delta v\) required for such a transfer, highlighting the fuel savings achieved by this specific orbital maneuver.
Incorrect
The question probes the understanding of orbital mechanics and the principles governing spacecraft trajectory adjustments, specifically focusing on the efficiency of different propulsive maneuvers. The concept of delta-v (\(\Delta v\)) is central here, representing the change in velocity required for a maneuver. For a Hohmann transfer orbit, which is the most fuel-efficient two-impulse maneuver for transferring between two circular coplanar orbits, the total \(\Delta v\) is the sum of the \(\Delta v\) required to leave the initial orbit and the \(\Delta v\) required to enter the final orbit. Let \(r_1\) be the radius of the initial circular orbit and \(r_2\) be the radius of the final circular orbit. The velocity in the initial circular orbit is \(v_1 = \sqrt{\frac{\mu}{r_1}}\), where \(\mu\) is the standard gravitational parameter of the central body. The velocity at the periapsis of the transfer ellipse (at radius \(r_1\)) is \(v_{p,transfer} = \sqrt{\mu \left(\frac{2}{r_1} – \frac{1}{a_{transfer}}\right)}\), where \(a_{transfer} = \frac{r_1 + r_2}{2}\) is the semi-major axis of the transfer ellipse. The first \(\Delta v\) is \(\Delta v_1 = v_{p,transfer} – v_1\). The velocity at the apoapsis of the transfer ellipse (at radius \(r_2\)) is \(v_{a,transfer} = \sqrt{\mu \left(\frac{2}{r_2} – \frac{1}{a_{transfer}}\right)}\). The velocity in the final circular orbit is \(v_2 = \sqrt{\frac{\mu}{r_2}}\). The second \(\Delta v\) is \(\Delta v_2 = v_2 – v_{a,transfer}\). The total \(\Delta v\) for a Hohmann transfer is \(\Delta v_{total} = \Delta v_1 + \Delta v_2\). Consider a scenario where a spacecraft is in a circular orbit around Earth at an altitude of 300 km and needs to transfer to a circular orbit at an altitude of 1000 km. Given: Radius of Earth \(R_E \approx 6371\) km Standard gravitational parameter of Earth \(\mu \approx 3.986 \times 10^5\) km\(^3\)/s\(^2\) Initial orbit radius \(r_1 = R_E + 300 \text{ km} = 6371 + 300 = 6671\) km Final orbit radius \(r_2 = R_E + 1000 \text{ km} = 6371 + 1000 = 7371\) km Initial circular velocity \(v_1 = \sqrt{\frac{\mu}{r_1}} = \sqrt{\frac{3.986 \times 10^5}{6671}} \approx \sqrt{59.75} \approx 7.73\) km/s Semi-major axis of transfer ellipse \(a_{transfer} = \frac{r_1 + r_2}{2} = \frac{6671 + 7371}{2} = \frac{14042}{2} = 7021\) km Velocity at periapsis of transfer ellipse \(v_{p,transfer} = \sqrt{\mu \left(\frac{2}{r_1} – \frac{1}{a_{transfer}}\right)} = \sqrt{3.986 \times 10^5 \left(\frac{2}{6671} – \frac{1}{7021}\right)}\) \(v_{p,transfer} = \sqrt{3.986 \times 10^5 \left(0.0002998 – 0.0001424\right)} = \sqrt{3.986 \times 10^5 \times 0.0001574} \approx \sqrt{62.74} \approx 7.92\) km/s First \(\Delta v_1 = v_{p,transfer} – v_1 \approx 7.92 – 7.73 = 0.19\) km/s Velocity at apoapsis of transfer ellipse \(v_{a,transfer} = \sqrt{\mu \left(\frac{2}{r_2} – \frac{1}{a_{transfer}}\right)} = \sqrt{3.986 \times 10^5 \left(\frac{2}{7371} – \frac{1}{7021}\right)}\) \(v_{a,transfer} = \sqrt{3.986 \times 10^5 \left(0.0002713 – 0.0001424\right)} = \sqrt{3.986 \times 10^5 \times 0.0001289} \approx \sqrt{51.38} \approx 7.17\) km/s Final circular velocity \(v_2 = \sqrt{\frac{\mu}{r_2}} = \sqrt{\frac{3.986 \times 10^5}{7371}} \approx \sqrt{54.07} \approx 7.35\) km/s Second \(\Delta v_2 = v_2 – v_{a,transfer} \approx 7.35 – 7.17 = 0.18\) km/s Total \(\Delta v_{total} = \Delta v_1 + \Delta v_2 \approx 0.19 + 0.18 = 0.37\) km/s. The question asks about the *efficiency* of maneuvers. While Hohmann transfers are generally the most fuel-efficient for coplanar transfers, other maneuvers exist. Bi-elliptic transfers, for instance, can be more efficient for large changes in orbital radius, especially when the ratio of final to initial radius is very high. However, they require more impulses and longer transfer times. For moderate changes in orbital radius, as implied by the typical context of such problems, the Hohmann transfer remains a benchmark for efficiency. The question is designed to test the understanding of the fundamental trade-offs in orbital maneuvers: fuel efficiency versus time of flight and complexity of execution. The most fuel-efficient method for a single plane change and orbit adjustment between two circular orbits is typically the Hohmann transfer, which minimizes the total \(\Delta v\). Other methods, like continuous thrust or low-thrust trajectories, might achieve the same change in velocity but over a much longer period and with different efficiency considerations related to specific impulse and engine type. However, within the context of impulsive maneuvers, the Hohmann transfer is the standard for minimal \(\Delta v\). Therefore, understanding the principles behind it and its comparative efficiency is crucial for aerospace engineering students at Siberian State Aerospace University. The calculation above demonstrates the minimal \(\Delta v\) required for such a transfer, highlighting the fuel savings achieved by this specific orbital maneuver.
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Question 21 of 30
21. Question
When designing a translunar injection maneuver for a mission departing from a stable low Earth orbit, what fundamental celestial mechanical parameter most critically dictates the overall energy budget and propellant mass required for the trajectory alteration, thereby influencing the mission’s feasibility and the selection of the most efficient transfer path?
Correct
The question probes the understanding of fundamental principles in orbital mechanics and the practical considerations for spacecraft trajectory design, particularly concerning the energy requirements for achieving specific orbital maneuvers. To reach a higher orbit from a lower one, a spacecraft must increase its total mechanical energy. This is typically achieved through propulsive burns. The most energy-efficient way to transition between two coplanar circular orbits is by using a Hohmann transfer orbit, which is an elliptical orbit tangent to both the initial and final circular orbits. The energy change required for such a maneuver is directly related to the difference in orbital radii and the gravitational parameter of the central body. While specific calculations are not required for this conceptual question, understanding the principles behind them is crucial. A Hohmann transfer involves two burns: one to enter the transfer ellipse from the initial circular orbit, and another to circularize the orbit at the higher altitude. Each burn requires a change in velocity, \(\Delta v\), which is provided by the spacecraft’s propulsion system. The magnitude of these \(\Delta v\) values, and thus the propellant required, is minimized by the Hohmann transfer compared to other, less direct transfer methods. The question asks about the primary factor influencing the feasibility and efficiency of such a transfer, specifically in the context of a mission originating from Earth orbit and targeting a lunar trajectory. This involves transitioning from a low Earth orbit (LEO) to a translunar injection (TLI) trajectory. The energy required for TLI is substantial because it not only needs to raise the spacecraft’s apogee to the Moon’s orbital distance but also impart sufficient velocity to escape Earth’s gravitational influence and reach the Moon. Therefore, the gravitational parameter of the central body (Earth, in this case) and the specific energy difference between the initial and target orbits are the most critical determinants of the mission’s propulsion requirements and overall feasibility. The efficiency of the transfer orbit itself (e.g., using a Hohmann-like transfer) is a design choice to minimize these requirements, but the fundamental energy budget is dictated by the celestial mechanics.
Incorrect
The question probes the understanding of fundamental principles in orbital mechanics and the practical considerations for spacecraft trajectory design, particularly concerning the energy requirements for achieving specific orbital maneuvers. To reach a higher orbit from a lower one, a spacecraft must increase its total mechanical energy. This is typically achieved through propulsive burns. The most energy-efficient way to transition between two coplanar circular orbits is by using a Hohmann transfer orbit, which is an elliptical orbit tangent to both the initial and final circular orbits. The energy change required for such a maneuver is directly related to the difference in orbital radii and the gravitational parameter of the central body. While specific calculations are not required for this conceptual question, understanding the principles behind them is crucial. A Hohmann transfer involves two burns: one to enter the transfer ellipse from the initial circular orbit, and another to circularize the orbit at the higher altitude. Each burn requires a change in velocity, \(\Delta v\), which is provided by the spacecraft’s propulsion system. The magnitude of these \(\Delta v\) values, and thus the propellant required, is minimized by the Hohmann transfer compared to other, less direct transfer methods. The question asks about the primary factor influencing the feasibility and efficiency of such a transfer, specifically in the context of a mission originating from Earth orbit and targeting a lunar trajectory. This involves transitioning from a low Earth orbit (LEO) to a translunar injection (TLI) trajectory. The energy required for TLI is substantial because it not only needs to raise the spacecraft’s apogee to the Moon’s orbital distance but also impart sufficient velocity to escape Earth’s gravitational influence and reach the Moon. Therefore, the gravitational parameter of the central body (Earth, in this case) and the specific energy difference between the initial and target orbits are the most critical determinants of the mission’s propulsion requirements and overall feasibility. The efficiency of the transfer orbit itself (e.g., using a Hohmann-like transfer) is a design choice to minimize these requirements, but the fundamental energy budget is dictated by the celestial mechanics.
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Question 22 of 30
22. Question
Consider a newly deployed experimental satellite for atmospheric research, operating in a highly elliptical orbit around Earth. Its perigee is designed to dip into the exosphere, a region with extremely low but non-zero atmospheric density. What is the most direct and significant consequence for the satellite’s orbital parameters due to this perigee interaction with the upper atmosphere, as studied at Siberian State Aerospace University?
Correct
The question probes the understanding of orbital mechanics and the implications of atmospheric drag on spacecraft, a core concept in aerospace engineering relevant to the Siberian State Aerospace University’s curriculum. While no direct calculation is required, the underlying principle involves understanding how atmospheric density at different altitudes affects orbital decay. Lower Earth Orbit (LEO) satellites experience more significant drag than those in higher orbits. The scenario describes a satellite in a highly elliptical orbit with its perigee dipping into the upper atmosphere. The primary concern for such a satellite is the increased rate of orbital decay due to atmospheric friction at its lowest point. This friction causes a loss of energy, which in turn lowers the apogee and eventually the perigee, leading to a spiraling descent. Therefore, the most immediate and significant consequence of the perigee’s interaction with the tenuous upper atmosphere is the accelerated decay of its orbital period and altitude. This is a direct result of the increased drag forces encountered during each perigee pass. The other options, while potentially related to spacecraft operations, are not the *most* immediate or direct consequence of perigee interaction with the atmosphere. For instance, increased solar radiation pressure is a factor in orbital dynamics but is not directly amplified by atmospheric interaction at perigee. Changes in the eccentricity of the orbit are a *result* of drag, not the primary consequence itself, and the effect on communication link stability is a secondary outcome of orbital decay.
Incorrect
The question probes the understanding of orbital mechanics and the implications of atmospheric drag on spacecraft, a core concept in aerospace engineering relevant to the Siberian State Aerospace University’s curriculum. While no direct calculation is required, the underlying principle involves understanding how atmospheric density at different altitudes affects orbital decay. Lower Earth Orbit (LEO) satellites experience more significant drag than those in higher orbits. The scenario describes a satellite in a highly elliptical orbit with its perigee dipping into the upper atmosphere. The primary concern for such a satellite is the increased rate of orbital decay due to atmospheric friction at its lowest point. This friction causes a loss of energy, which in turn lowers the apogee and eventually the perigee, leading to a spiraling descent. Therefore, the most immediate and significant consequence of the perigee’s interaction with the tenuous upper atmosphere is the accelerated decay of its orbital period and altitude. This is a direct result of the increased drag forces encountered during each perigee pass. The other options, while potentially related to spacecraft operations, are not the *most* immediate or direct consequence of perigee interaction with the atmosphere. For instance, increased solar radiation pressure is a factor in orbital dynamics but is not directly amplified by atmospheric interaction at perigee. Changes in the eccentricity of the orbit are a *result* of drag, not the primary consequence itself, and the effect on communication link stability is a secondary outcome of orbital decay.
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Question 23 of 30
23. Question
Consider a newly deployed, perfectly circular orbital path for a small, experimental satellite designed for atmospheric research, positioned at an altitude of 250 kilometers above the Earth’s surface. Given the inherent presence of residual atmospheric gases even at this altitude, what is the most probable long-term consequence for the satellite’s orbital trajectory without any corrective maneuvers?
Correct
The question probes the understanding of orbital mechanics and the implications of atmospheric drag on spacecraft, a core concept in aerospace engineering programs at Siberian State Aerospace University. While no direct calculation is required, the underlying principle involves the relationship between orbital altitude, atmospheric density, and the rate of orbital decay. A lower orbit, even if initially stable, will experience greater atmospheric drag due to higher atmospheric density. This drag acts as a decelerating force, reducing the spacecraft’s orbital velocity. As velocity decreases, the orbital energy also decreases, causing the orbit to shrink. If the orbit shrinks sufficiently, it will intersect with denser atmospheric layers, accelerating the decay process until re-entry. Therefore, a spacecraft in a lower Earth orbit, even one that is circular, will inevitably experience a gradual decrease in altitude over time due to this persistent, albeit small, atmospheric drag. The rate of decay is influenced by factors like the spacecraft’s ballistic coefficient (ratio of mass to drag area) and solar activity, which affects atmospheric density. However, the fundamental principle remains that any orbit below the exosphere is subject to some degree of drag, leading to eventual decay.
Incorrect
The question probes the understanding of orbital mechanics and the implications of atmospheric drag on spacecraft, a core concept in aerospace engineering programs at Siberian State Aerospace University. While no direct calculation is required, the underlying principle involves the relationship between orbital altitude, atmospheric density, and the rate of orbital decay. A lower orbit, even if initially stable, will experience greater atmospheric drag due to higher atmospheric density. This drag acts as a decelerating force, reducing the spacecraft’s orbital velocity. As velocity decreases, the orbital energy also decreases, causing the orbit to shrink. If the orbit shrinks sufficiently, it will intersect with denser atmospheric layers, accelerating the decay process until re-entry. Therefore, a spacecraft in a lower Earth orbit, even one that is circular, will inevitably experience a gradual decrease in altitude over time due to this persistent, albeit small, atmospheric drag. The rate of decay is influenced by factors like the spacecraft’s ballistic coefficient (ratio of mass to drag area) and solar activity, which affects atmospheric density. However, the fundamental principle remains that any orbit below the exosphere is subject to some degree of drag, leading to eventual decay.
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Question 24 of 30
24. Question
Consider a newly deployed observational satellite for atmospheric research operating in a low Earth orbit around the planet. Recent solar activity has caused a temporary but significant increase in the density of the upper atmosphere. What is the most likely immediate consequence for the satellite’s orbital parameters due to this enhanced atmospheric drag?
Correct
The question probes the understanding of orbital mechanics and the implications of atmospheric drag on satellite trajectories, a fundamental concept in aerospace engineering relevant to the Siberian State Aerospace University’s curriculum. The scenario describes a low Earth orbit (LEO) satellite experiencing increased atmospheric density. This increased density leads to greater frictional forces, commonly referred to as atmospheric drag. Atmospheric drag acts as a decelerating force, opposing the satellite’s velocity. In orbit, a satellite’s speed is directly related to its altitude; a faster satellite is in a lower orbit, and a slower satellite is in a higher orbit (assuming a circular orbit for simplicity, though the principle holds for elliptical orbits). When drag reduces the satellite’s speed, its orbital energy decreases. According to Kepler’s laws and conservation of energy principles in orbital mechanics, a decrease in orbital energy results in a decrease in the semi-major axis of the orbit. A smaller semi-major axis corresponds to a lower orbital altitude. Therefore, increased atmospheric density, leading to greater drag, will cause the satellite’s orbital altitude to decrease over time. The rate of this decrease is influenced by factors such as the satellite’s shape, surface area, mass, and the specific atmospheric density profile. The core concept is the inverse relationship between orbital speed and altitude in a gravitational field, and how external forces like drag perturb this balance.
Incorrect
The question probes the understanding of orbital mechanics and the implications of atmospheric drag on satellite trajectories, a fundamental concept in aerospace engineering relevant to the Siberian State Aerospace University’s curriculum. The scenario describes a low Earth orbit (LEO) satellite experiencing increased atmospheric density. This increased density leads to greater frictional forces, commonly referred to as atmospheric drag. Atmospheric drag acts as a decelerating force, opposing the satellite’s velocity. In orbit, a satellite’s speed is directly related to its altitude; a faster satellite is in a lower orbit, and a slower satellite is in a higher orbit (assuming a circular orbit for simplicity, though the principle holds for elliptical orbits). When drag reduces the satellite’s speed, its orbital energy decreases. According to Kepler’s laws and conservation of energy principles in orbital mechanics, a decrease in orbital energy results in a decrease in the semi-major axis of the orbit. A smaller semi-major axis corresponds to a lower orbital altitude. Therefore, increased atmospheric density, leading to greater drag, will cause the satellite’s orbital altitude to decrease over time. The rate of this decrease is influenced by factors such as the satellite’s shape, surface area, mass, and the specific atmospheric density profile. The core concept is the inverse relationship between orbital speed and altitude in a gravitational field, and how external forces like drag perturb this balance.
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Question 25 of 30
25. Question
Consider a meteorological satellite operated by the Siberian State Aerospace University, initially placed in a near-circular low Earth orbit. Over time, due to residual atmospheric density at its operational altitude, the satellite experiences a consistent but small amount of atmospheric drag. Which of the following accurately describes the satellite’s orbital parameters as this drag effect becomes more pronounced?
Correct
The question probes the understanding of orbital mechanics and the implications of atmospheric drag on spacecraft, a fundamental concept in aerospace engineering, particularly relevant to the Siberian State Aerospace University’s focus on space exploration and satellite technology. The scenario describes a satellite in a low Earth orbit experiencing atmospheric drag. Atmospheric drag is a force that opposes the motion of an object through the atmosphere. For a satellite in LEO, this drag causes a gradual loss of orbital energy. This energy loss manifests as a decrease in orbital velocity and a corresponding decrease in orbital altitude. As the altitude decreases, the satellite enters denser atmospheric layers, leading to increased drag and a faster decay of its orbit. The key principle here is the conservation of energy in an orbit, modified by non-conservative forces like drag. While the total mechanical energy of an object in orbit is typically \( E = -\frac{GMm}{2a} \), where \( G \) is the gravitational constant, \( M \) is the mass of the central body, \( m \) is the mass of the orbiting body, and \( a \) is the semi-major axis, atmospheric drag acts to reduce this energy. A reduction in orbital energy leads to a decrease in the semi-major axis. For a circular orbit, the velocity is given by \( v = \sqrt{\frac{GM}{r}} \), where \( r \) is the orbital radius. As the semi-major axis decreases due to drag, the orbital radius also decreases, and consequently, the orbital velocity *increases* to maintain a stable (though decaying) orbit. This counter-intuitive increase in velocity is a critical point. The satellite is not accelerating in the traditional sense due to propulsion; rather, it is converting potential energy into kinetic energy as it spirals inward. Therefore, the most accurate description of the satellite’s state is that its orbital velocity is increasing as its altitude decreases due to atmospheric drag.
Incorrect
The question probes the understanding of orbital mechanics and the implications of atmospheric drag on spacecraft, a fundamental concept in aerospace engineering, particularly relevant to the Siberian State Aerospace University’s focus on space exploration and satellite technology. The scenario describes a satellite in a low Earth orbit experiencing atmospheric drag. Atmospheric drag is a force that opposes the motion of an object through the atmosphere. For a satellite in LEO, this drag causes a gradual loss of orbital energy. This energy loss manifests as a decrease in orbital velocity and a corresponding decrease in orbital altitude. As the altitude decreases, the satellite enters denser atmospheric layers, leading to increased drag and a faster decay of its orbit. The key principle here is the conservation of energy in an orbit, modified by non-conservative forces like drag. While the total mechanical energy of an object in orbit is typically \( E = -\frac{GMm}{2a} \), where \( G \) is the gravitational constant, \( M \) is the mass of the central body, \( m \) is the mass of the orbiting body, and \( a \) is the semi-major axis, atmospheric drag acts to reduce this energy. A reduction in orbital energy leads to a decrease in the semi-major axis. For a circular orbit, the velocity is given by \( v = \sqrt{\frac{GM}{r}} \), where \( r \) is the orbital radius. As the semi-major axis decreases due to drag, the orbital radius also decreases, and consequently, the orbital velocity *increases* to maintain a stable (though decaying) orbit. This counter-intuitive increase in velocity is a critical point. The satellite is not accelerating in the traditional sense due to propulsion; rather, it is converting potential energy into kinetic energy as it spirals inward. Therefore, the most accurate description of the satellite’s state is that its orbital velocity is increasing as its altitude decreases due to atmospheric drag.
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Question 26 of 30
26. Question
When designing a mission for the Siberian State Aerospace University to place a reconnaissance satellite into a stable, near-circular orbit around Earth, what fundamental physical principle must be precisely adhered to for the satellite to maintain its trajectory without continuous propulsion?
Correct
The question probes the understanding of orbital mechanics and the fundamental principles governing spacecraft trajectories, particularly in the context of achieving a stable orbit around a celestial body. To achieve a stable orbit, a spacecraft must possess a tangential velocity that precisely balances the gravitational pull of the celestial body at a given altitude. This balance ensures that the spacecraft continuously falls towards the body but also moves sideways fast enough to miss it, resulting in a continuous curved path. Consider a simplified scenario where a satellite is launched from the surface of a planet with mass \(M\) and radius \(R\). To achieve a circular orbit at an altitude \(h\) above the surface, the satellite’s velocity \(v\) must satisfy the condition where the centripetal force required for circular motion equals the gravitational force exerted by the planet. The centripetal force is given by \(F_c = \frac{mv^2}{r}\), where \(m\) is the satellite’s mass and \(r\) is the orbital radius. The gravitational force is given by \(F_g = G\frac{Mm}{r^2}\), where \(G\) is the gravitational constant. Equating these forces for a circular orbit: \[ \frac{mv^2}{r} = G\frac{Mm}{r^2} \] Solving for \(v\): \[ v^2 = G\frac{M}{r} \] \[ v = \sqrt{G\frac{M}{r}} \] The orbital radius \(r\) is the sum of the planet’s radius and the altitude: \(r = R + h\). The question asks about the critical factor determining the successful establishment of a stable orbit. This velocity is not arbitrary; it is a specific value dictated by the physics of gravity and motion. If the velocity is too low, gravity will pull the spacecraft back to the planet. If the velocity is too high, the spacecraft will escape the planet’s gravitational influence or enter a highly elliptical, potentially unstable orbit. Therefore, achieving the precise tangential velocity required to balance gravitational acceleration at the desired orbital radius is the paramount condition for a stable orbit. This concept is fundamental to all space missions launched from Siberian State Aerospace University, from satellite deployment to interplanetary probes. Understanding this balance is crucial for mission planning and execution, ensuring the longevity and success of space endeavors.
Incorrect
The question probes the understanding of orbital mechanics and the fundamental principles governing spacecraft trajectories, particularly in the context of achieving a stable orbit around a celestial body. To achieve a stable orbit, a spacecraft must possess a tangential velocity that precisely balances the gravitational pull of the celestial body at a given altitude. This balance ensures that the spacecraft continuously falls towards the body but also moves sideways fast enough to miss it, resulting in a continuous curved path. Consider a simplified scenario where a satellite is launched from the surface of a planet with mass \(M\) and radius \(R\). To achieve a circular orbit at an altitude \(h\) above the surface, the satellite’s velocity \(v\) must satisfy the condition where the centripetal force required for circular motion equals the gravitational force exerted by the planet. The centripetal force is given by \(F_c = \frac{mv^2}{r}\), where \(m\) is the satellite’s mass and \(r\) is the orbital radius. The gravitational force is given by \(F_g = G\frac{Mm}{r^2}\), where \(G\) is the gravitational constant. Equating these forces for a circular orbit: \[ \frac{mv^2}{r} = G\frac{Mm}{r^2} \] Solving for \(v\): \[ v^2 = G\frac{M}{r} \] \[ v = \sqrt{G\frac{M}{r}} \] The orbital radius \(r\) is the sum of the planet’s radius and the altitude: \(r = R + h\). The question asks about the critical factor determining the successful establishment of a stable orbit. This velocity is not arbitrary; it is a specific value dictated by the physics of gravity and motion. If the velocity is too low, gravity will pull the spacecraft back to the planet. If the velocity is too high, the spacecraft will escape the planet’s gravitational influence or enter a highly elliptical, potentially unstable orbit. Therefore, achieving the precise tangential velocity required to balance gravitational acceleration at the desired orbital radius is the paramount condition for a stable orbit. This concept is fundamental to all space missions launched from Siberian State Aerospace University, from satellite deployment to interplanetary probes. Understanding this balance is crucial for mission planning and execution, ensuring the longevity and success of space endeavors.
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Question 27 of 30
27. Question
Consider a scenario where a satellite initially in a highly elliptical Earth orbit, with a perigee altitude of 150 km and an apogee altitude of 500 km, undergoes a propulsive maneuver at perigee to achieve a perfectly circular orbit. If a second, identical satellite performs a similar circularization maneuver, but at an apogee altitude of 300 km, which of the following statements most accurately describes the resulting orbital periods of the two satellites, assuming both maneuvers are executed to achieve the lowest possible circular orbit at their respective maneuver points?
Correct
The question probes the understanding of orbital mechanics and the implications of atmospheric drag on spacecraft, a core concept in aerospace engineering relevant to the Siberian State Aerospace University Entrance Exam. While no direct calculation is presented, the reasoning involves understanding that a lower perigee, even if circularized, will experience significantly higher atmospheric drag. This increased drag leads to a faster decay of the orbital energy and thus a shorter orbital period. The concept of orbital period is directly related to the semi-major axis of the orbit. For a circular orbit, the period \(T\) is given by \(T = 2\pi \sqrt{\frac{a^3}{\mu}}\), where \(a\) is the semi-major axis and \(\mu\) is the standard gravitational parameter of the central body. A shorter orbital period implies a smaller semi-major axis. Therefore, an orbit with a lower perigee, even after a circularization maneuver that results in a lower altitude, will have a smaller semi-major axis and consequently a shorter orbital period compared to a higher, less affected orbit. The key is that the circularization maneuver at a lower altitude inherently places the spacecraft into an orbit with a smaller semi-major axis, directly impacting its period. The other options are incorrect because while eccentricity affects orbital period in a more complex way (related to the average distance), for a circular orbit, the semi-major axis is the sole determinant. A higher apogee would imply a larger semi-major axis and thus a longer period. A higher eccentricity, while not directly applicable to a perfectly circular orbit, would generally lead to a longer period for a given semi-major axis if the orbit were elliptical.
Incorrect
The question probes the understanding of orbital mechanics and the implications of atmospheric drag on spacecraft, a core concept in aerospace engineering relevant to the Siberian State Aerospace University Entrance Exam. While no direct calculation is presented, the reasoning involves understanding that a lower perigee, even if circularized, will experience significantly higher atmospheric drag. This increased drag leads to a faster decay of the orbital energy and thus a shorter orbital period. The concept of orbital period is directly related to the semi-major axis of the orbit. For a circular orbit, the period \(T\) is given by \(T = 2\pi \sqrt{\frac{a^3}{\mu}}\), where \(a\) is the semi-major axis and \(\mu\) is the standard gravitational parameter of the central body. A shorter orbital period implies a smaller semi-major axis. Therefore, an orbit with a lower perigee, even after a circularization maneuver that results in a lower altitude, will have a smaller semi-major axis and consequently a shorter orbital period compared to a higher, less affected orbit. The key is that the circularization maneuver at a lower altitude inherently places the spacecraft into an orbit with a smaller semi-major axis, directly impacting its period. The other options are incorrect because while eccentricity affects orbital period in a more complex way (related to the average distance), for a circular orbit, the semi-major axis is the sole determinant. A higher apogee would imply a larger semi-major axis and thus a longer period. A higher eccentricity, while not directly applicable to a perfectly circular orbit, would generally lead to a longer period for a given semi-major axis if the orbit were elliptical.
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Question 28 of 30
28. Question
Consider two satellites orbiting Earth. Satellite Alpha maintains a nearly circular orbit at an average altitude of 400 kilometers. Satellite Beta, however, follows a highly elliptical orbit with a perigee of 150 kilometers and an apogee of 1000 kilometers. Both satellites are subject to the same atmospheric drag forces when they are within the upper atmosphere. Which statement accurately describes the comparative orbital decay rates for Satellite Alpha and Satellite Beta, considering the principles of orbital mechanics and atmospheric interaction relevant to space missions studied at Siberian State Aerospace University Entrance Exam?
Correct
The question probes the understanding of orbital mechanics and the implications of atmospheric drag on spacecraft. While no direct calculation is performed, the reasoning involves understanding that a lower perigee, especially within the denser layers of the atmosphere, will result in a greater rate of orbital decay due to increased drag. A higher apogee, conversely, would mean the spacecraft spends less time in the denser atmospheric regions, thus experiencing less drag. Therefore, an orbit with a higher apogee and a lower perigee, while still elliptical, would experience a net *increase* in the rate of orbital decay compared to a more circular orbit at the same average altitude, because the perigee is significantly affected by atmospheric friction. The key is that the *rate* of decay is primarily driven by the conditions at the lowest point of the orbit. A highly elliptical orbit with a very low perigee will decay much faster than a near-circular orbit at a moderate altitude.
Incorrect
The question probes the understanding of orbital mechanics and the implications of atmospheric drag on spacecraft. While no direct calculation is performed, the reasoning involves understanding that a lower perigee, especially within the denser layers of the atmosphere, will result in a greater rate of orbital decay due to increased drag. A higher apogee, conversely, would mean the spacecraft spends less time in the denser atmospheric regions, thus experiencing less drag. Therefore, an orbit with a higher apogee and a lower perigee, while still elliptical, would experience a net *increase* in the rate of orbital decay compared to a more circular orbit at the same average altitude, because the perigee is significantly affected by atmospheric friction. The key is that the *rate* of decay is primarily driven by the conditions at the lowest point of the orbit. A highly elliptical orbit with a very low perigee will decay much faster than a near-circular orbit at a moderate altitude.
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Question 29 of 30
29. Question
Consider a scenario where a newly launched satellite from the Baikonur Cosmodrome needs to be maneuvered from its initial low Earth parking orbit into a stable geostationary orbit. Which of the following orbital transfer strategies, when executed with precise burns, would represent the most propellant-efficient method for achieving this transition, aligning with the core principles of astrodynamics taught at Siberian State Aerospace University?
Correct
The question probes understanding of orbital mechanics and the principles governing spacecraft trajectory adjustments, specifically concerning the Hohmann transfer orbit. A Hohmann transfer is an elliptical orbit that connects two coplanar circular orbits of different radii. The maneuver involves two impulsive burns: one to leave the initial circular orbit and enter the transfer ellipse, and a second to circularize the orbit at the destination. To determine the most efficient method for a spacecraft to transition from a lower Earth orbit to a higher geostationary orbit, we must consider the energy requirements and the principles of orbital mechanics. The Hohmann transfer orbit is the most fuel-efficient two-impulse maneuver for transferring between two coplanar circular orbits. It minimizes the total change in velocity (\(\Delta V\)) required. The first burn increases the spacecraft’s velocity, raising its apogee to the altitude of the target orbit. The second burn, performed at apogee, further increases the velocity to circularize the orbit at the higher altitude. While other transfer orbits exist (e.g., bi-elliptic transfers, which can be more efficient for very large orbital changes but require more burns), the Hohmann transfer is generally the benchmark for efficiency between moderately separated circular orbits. The Siberian State Aerospace University’s curriculum emphasizes fundamental principles of astrodynamics and space mission design. Understanding orbital maneuvers like the Hohmann transfer is crucial for designing efficient and cost-effective space missions, a core competency for aerospace engineers graduating from the university. This question assesses the candidate’s grasp of these foundational concepts, which are directly applicable to satellite deployment, interplanetary missions, and space station logistics. The efficiency of a Hohmann transfer is directly tied to minimizing propellant mass, a critical factor in mission cost and payload capacity. Therefore, selecting this method reflects a sound understanding of practical space engineering constraints.
Incorrect
The question probes understanding of orbital mechanics and the principles governing spacecraft trajectory adjustments, specifically concerning the Hohmann transfer orbit. A Hohmann transfer is an elliptical orbit that connects two coplanar circular orbits of different radii. The maneuver involves two impulsive burns: one to leave the initial circular orbit and enter the transfer ellipse, and a second to circularize the orbit at the destination. To determine the most efficient method for a spacecraft to transition from a lower Earth orbit to a higher geostationary orbit, we must consider the energy requirements and the principles of orbital mechanics. The Hohmann transfer orbit is the most fuel-efficient two-impulse maneuver for transferring between two coplanar circular orbits. It minimizes the total change in velocity (\(\Delta V\)) required. The first burn increases the spacecraft’s velocity, raising its apogee to the altitude of the target orbit. The second burn, performed at apogee, further increases the velocity to circularize the orbit at the higher altitude. While other transfer orbits exist (e.g., bi-elliptic transfers, which can be more efficient for very large orbital changes but require more burns), the Hohmann transfer is generally the benchmark for efficiency between moderately separated circular orbits. The Siberian State Aerospace University’s curriculum emphasizes fundamental principles of astrodynamics and space mission design. Understanding orbital maneuvers like the Hohmann transfer is crucial for designing efficient and cost-effective space missions, a core competency for aerospace engineers graduating from the university. This question assesses the candidate’s grasp of these foundational concepts, which are directly applicable to satellite deployment, interplanetary missions, and space station logistics. The efficiency of a Hohmann transfer is directly tied to minimizing propellant mass, a critical factor in mission cost and payload capacity. Therefore, selecting this method reflects a sound understanding of practical space engineering constraints.
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Question 30 of 30
30. Question
Consider a scenario where a defunct satellite in a circular Low Earth Orbit (LEO) at an altitude of 400 km above Earth’s surface needs to be safely de-orbited. The mission control team at Siberian State Aerospace University’s Space Operations Center is planning the final de-orbit burn. To ensure the most efficient and timely atmospheric re-entry, minimizing the time spent in orbit before decay, which orientation of the satellite’s thruster firing relative to its orbital velocity vector would be most appropriate?
Correct
The question probes the understanding of orbital mechanics and the factors influencing satellite maneuverability in the context of orbital debris mitigation, a critical area for space agencies like those associated with Siberian State Aerospace University. The scenario involves a satellite in a low Earth orbit (LEO) needing to perform a de-orbit burn. The key principle here is that the effectiveness and efficiency of an orbital maneuver, particularly a de-orbit burn, are directly related to the satellite’s velocity vector at the time of the burn. A burn performed tangential to the orbital path, in the direction opposite to the satellite’s velocity, will result in the largest reduction in orbital energy and thus the most efficient de-orbit. This is because the change in velocity (\(\Delta v\)) is applied directly to reduce the orbital speed, leading to a faster decay into the atmosphere. Performing the burn perpendicular to the velocity vector would primarily change the inclination or the orientation of the orbit, not its energy significantly. A burn in the direction of velocity would increase orbital energy, which is counterproductive for de-orbiting. Therefore, the most effective strategy for a timely and efficient de-orbit burn is to execute it precisely opposite to the satellite’s current velocity vector. This maximizes the reduction in orbital speed, leading to a quicker and more predictable atmospheric re-entry, minimizing the risk of long-term orbital debris. This understanding is fundamental for mission planning and space situational awareness, areas of significant research and education at Siberian State Aerospace University.
Incorrect
The question probes the understanding of orbital mechanics and the factors influencing satellite maneuverability in the context of orbital debris mitigation, a critical area for space agencies like those associated with Siberian State Aerospace University. The scenario involves a satellite in a low Earth orbit (LEO) needing to perform a de-orbit burn. The key principle here is that the effectiveness and efficiency of an orbital maneuver, particularly a de-orbit burn, are directly related to the satellite’s velocity vector at the time of the burn. A burn performed tangential to the orbital path, in the direction opposite to the satellite’s velocity, will result in the largest reduction in orbital energy and thus the most efficient de-orbit. This is because the change in velocity (\(\Delta v\)) is applied directly to reduce the orbital speed, leading to a faster decay into the atmosphere. Performing the burn perpendicular to the velocity vector would primarily change the inclination or the orientation of the orbit, not its energy significantly. A burn in the direction of velocity would increase orbital energy, which is counterproductive for de-orbiting. Therefore, the most effective strategy for a timely and efficient de-orbit burn is to execute it precisely opposite to the satellite’s current velocity vector. This maximizes the reduction in orbital speed, leading to a quicker and more predictable atmospheric re-entry, minimizing the risk of long-term orbital debris. This understanding is fundamental for mission planning and space situational awareness, areas of significant research and education at Siberian State Aerospace University.